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3 years ago

X^2-7×+10 solve for quadratic formula.

Mathematics

2 answers:

horsena [70]3 years ago

8 0

Hey, did u mean solve using quadratic formula? If so... the image should help

sorry it’s a bit messy but I hope this helps.. if u didn’t mean to be solved this way please tell me and I’ll do my best to help :)

nordsb [41]3 years ago

5 0

What does that even mean

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Francisco spent 25 minutes on the internet yesterday is this is 5/6 of the time she spent on the computer how long did she spend

m_a_m_a [10]

30 minutes. the easiest way is to use the opposite of the fraction. divide 25 / 5= 5. now multiply by 6. 5*6= 30.

7 0

3 years ago

What's the difference between 126 1/4 78 2/3

Stels [109]

Difference means subtract, so we use subtraction:

*first we need to make the fractions have the same denominator

1/4 = 3/12
2/3 = 8/12

126(3/12) - 78(8/12)
*since the fraction in the first term is smaller than the second, make it improper

125(15/12) - 78(8/12)

now simply subtract:

125 - 78
= 47

15 - 8
= 7
* this is now (7/12)

now put them back together:

47(7/12)

That's the final answer!

3 0

3 years ago

If a parallelogram has diagonals that are perpendicular bisectors of each other, what is the most descriptive name for it?

Feliz [49]

Both a rhombus and a rectangle have diagonals that are perpendicular bisectors, but the ones formed in a square are all congruent, so that is probably the most descriptive one.

6 0

3 years ago

Please help thank you so much!

Illusion [34]

Answer:

Step-by-step explanation:

Average =

Sum

Count

332

= 83

4 0

3 years ago

A manufacturer produces light bulbs that have a mean life of at least 500 hours when the production process is working properly.

denpristay [2]

Answer:

We conclude that the population mean light bulb life is at least 500 hours at the significance level of 0.01.

Step-by-step explanation:

We are given that a manufacturer produces light bulbs that have a mean life of at least 500 hours when the production process is working properly. The population standard deviation is 50 hours and the light bulb life is normally distributed.

You select a sample of 100 light bulbs and find mean bulb life is 490 hours.

Let $\mu$ = population mean light bulb life.

So, Null Hypothesis, $H_0$ : $\mu \geq$ 500 hours {means that the population mean light bulb life is at least 500 hours}

Alternate Hypothesis, $H_A$ : $\mu$ < 500 hours {means that the population mean light bulb life is below 500 hours}

The test statistics that would be used here One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean bulb life = 490 hours

σ = population standard deviation = 50 hours

n = sample of light bulbs = 100

So, the test statistics = $\frac{490-500}{\frac{50}{\sqrt{100} } }$

= -2

The value of z test statistics is -2.

Now, at 0.01 significance level the z table gives critical value of -2.33 for left-tailed test.

Since our test statistic is higher than the critical value of z as -2 > -2.33, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the population mean light bulb life is at least 500 hours.

7 0

3 years ago