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Harman [31]
4 years ago
7

Which statement is true about the end behavior of the graphed function?

Mathematics
1 answer:
Sloan [31]4 years ago
7 0

D. As the x-values go to negative infinity, the function's values go to positive infinity.

Step-by-step explanation:

In the diagram you notice as the values of x increase to the far negative value, the function's output values increase to positive infinity.

For example at ;

x=-2, f(x)=0

x=-3, f(x)= 16

x= -4, f(x)= >64

This shows that as x values approach -∞, f(x) approach +∞

Learn More

Behavior of a function:brainly.com/question/12052868

Keywords :statement, true,end behavior, graph, function

#LearnwithBrainly

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Given the force field F, find the work required to move an object on the given oriented curve. F = (y, - x) on the path consisti
timofeeve [1]

Answer:

0

Step-by-step explanation:

We want to compute the curve integral (or line integral)

\bf \int_{C}F

where the force field F is defined by

F(x,y) = (y, -x)

and C is the path consisting of the line segment from (1, 5) to (0, 0) followed by the line segment from (0, 0) to (0, 9).

We can write  

C = \bf C_1+C_2

where  

\bf C_1 =  line segment from (1, 5) to (0, 0)  

\bf C_2 = line segment from (0, 0) to (0, 9)

so,

\bf \int_{C}F=\int_{C_1}F+\int_{C_2}F

Given 2 points P, Q in the plane, we can parameterize the line segment joining P and Q with

<em>r(t) = tQ + (1-t)P for 0 ≤ t ≤ 1 </em>

Hence \bf C_1 can be parameterized as

\bf r_1(t) = (1-t, 5-5t) for 0 ≤ t ≤ 1

and \bf C_2 can be parameterized as

\bf r_2(t) = (0, 9t) for 0 ≤ t ≤ 1

The derivatives are

\bf r_1'(t) = (-1, -5)

\bf r_2'(t) = (0, 9)

and

\bf \int_{C_1}F=\int_{0}^{1}F(r_1(t))\circ r_1'(t)dt=\int_{0}^{1}(5-5t,t-1)\circ (-1,-5)dt=0

\bf \int_{C_2}F=\int_{0}^{1}F(r_2(t))\circ r_2'(t)dt=\int_{0}^{1}(9t,0)\circ (0,-9)dt=0

In consequence,

\bf \int_{C}F=0

6 0
4 years ago
A right triangle has side lengths a, b, and c as shown below.
Marta_Voda [28]

Answer:

Step-by-step explanation:

7 0
3 years ago
What is the approximate length of arc s on the circle below? Use 3.14 for
ryzh [129]

The length of arc is 69.1 feet

<em><u>Solution:</u></em>

<em><u>The length of arc when angle given in degrees is given as:</u></em>

Arc\ length = \frac{ \theta }{360} \times 2 \pi r

Where,

r is the radius

\theta is the central angle in degrees

From given,

r = 12\ feet\\\\\theta = 330^{\circ}

<em><u>Substituting the values we get,</u></em>

Arc\ length = \frac{ 330 }{360} \times 2 \times 3.14 \times 12\\\\Arc\ length = \frac{ 330 }{360} \times 6.28 \times 12\\\\Arc\ length = 69.08 \approx 69.1

Thus the length of arc is 69.1 feet

5 0
3 years ago
Someone help me out with this and please get it all correct.
Law Incorporation [45]

Answer:

Step-by-step explanation:

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Answer:
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Step by step explanation:
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