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Fofino [41]
3 years ago
6

The school band is selling tickets for a chance to win an Ipad. Lucy bought 20 out of the 200 tickets sold. What percent chance

does Lucy have of winning the Ipad?
Mathematics
2 answers:
mel-nik [20]3 years ago
6 0

Answer:

She has a 10% chance.

Step-by-step explanation:

To make this easier on our selves let's divide each by 2.

That makes Lucy hold 10 tickets for the 100 tickets available.

10/100 = 10%

Any numerator that is over 100 is the percentage

Say if I had 52/100 I would have 52%

irga5000 [103]3 years ago
3 0

Answer:

Lucy has a 10% chance of winning the Ipad.

Step-by-step explanation:

divide 20 by 200: 20/200= 0.1

now to find the percent multiply the decimal by 100

0.1 * 100= 10

She has a 10% chance of winning the Ipad

hope this helps :)

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HELP! I'll mark you the brainest and give you all my points !! (Show all work)
Paha777 [63]

1. F(3)= -2(3)-5

-6-5

F(3)=-11

2. F(3)= -2(3)^2-4

-6^2-4

36-4

F(3)=32

3. F(x)=−2x−5

For: x=−2, f(x) is:f(−2)=(−2×−2)−5=4−5=−1

For: x=−1, f(x) is:f(−1)=(−2×−1)−5=2−5=−3

For: x=1, f(x) is:f(1)=(−2×1)−5=−2−5=−7

For: x=2, f(x) is:f(2)=(−2×2)−5=−4−5=−9

The Range is:

{−1,−3,−7,−9}

4. -80, -110

4 0
3 years ago
Read 2 more answers
Write the equation of the line parallel to Y equals 2/3X +1 through the point (0,-4)  use slope intercept form
Andrew [12]

Writing the slope-intercept form of a linear equation, we have:

y=mx+b

Where m is the slope and b is the y-intercept.

Since parallel lines have the same slope, we can see that the slope of the line y = 2/3x + 1 is equal m = 2/3, so for our equation we also have m = 2/3.

Now, using the point (0, -4), we have:

\begin{gathered} y=\frac{2}{3}x+b \\ (0,-4)\colon \\ -4=\frac{2}{3}\cdot0+b \\ b+0=-4 \\ b=-4 \end{gathered}

So our equation is:

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7 0
1 year ago
A metallurgist has one alloy containing 34% copper another containing 48% copper. How many pounds of each alloy must he use to m
Zielflug [23.3K]

Answer:

<h2>36.14 pounds of 34% copper alloy and 9.86 pounds of 48% copper alloy</h2>

Step-by-step explanation:

        First alloy contains 34% copper and the second alloy contains 48% alloy.

We wish to make 46 pounds of a third alloy containing 37% copper.

       Let the weight of first alloy used be x in pounds and the weight of second alloy used be y in pounds.

       Total weight = 46\text{ }pounds=x+y        -(i)

      Total weight of copper = 37\%\text{ of 46 pounds = }34\%\text{ of }x\text{ pounds + }48\%\text{ of }y\text{ pounds }

       \dfrac{37\times 46}{100}=\dfrac{34x}{100}+\dfrac{48y}{100}\\\\ 34x+48y=1702        -(ii)

       Subtracting 34 times first equation from second equation,

34x+48y-34x-34y=1702-34\times46\\14y=138\\y=9.857\text{ }pounds \\x=36.143\text{ }pounds

∴ 36.14 pounds of first alloy and 9.86 pounds of second alloy were used.

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3 years ago
Which statement about this equation is true?
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Help please?????????
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