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vredina [299]
3 years ago
14

11. factor the expression. k2 – 16h2 (k 4h)(k – 4h) (k – 4h2)(k 4) h2(k 4)(k – 4) (k 4h)(k 4h)

Mathematics
2 answers:
ANEK [815]3 years ago
7 0
Use\ a^2-b^2=(a-b)(a+b)\\\\k^2-16h^2=k^2-4^2h^2=k^2-(4h)^2=(k-4h)(k+4h)
RoseWind [281]3 years ago
7 0

Answer:

The correct option is 1.

Step-by-step explanation:

The given expression is

k^2-16h^2

It can be rewritten as

k^2-(4h)^2               .... (1)

The formula for difference of squares:

a^2-b^2=(a-b)(a+b)

In equation (1), a=h and b=4h. Using the above formula we get

k^2-(4h)^2=(k-4h)(k+4h)

The factor form of given expression is (k-4h)(k+4h). Therefore the correct option is 1.

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12 cos theta minus 16 sin theta is equal to zero find 2 sin theta + cos theta​
gayaneshka [121]

Answer:

2sinθ + cosθ = 2

Step-by-step explanation:

12 cos θ - 16 sinθ = 0

=> 3 cos θ -4 sin θ = 0

=> tanθ = 3/4

let P = 3x

B = 4x

=> H= 5x

=> sinθ = P/H = 3/5

cosθ = B/H = 4/5

2sinθ + cosθ

= 2× 3/5 + 4/5

= 6/5+4/5

= 10/5

= 2

=> 2sinθ + cosθ = 2

5 0
2 years ago
Read 2 more answers
The perimeter, P, of a rectangle is the sum of twice the length and twice the width.
LekaFEV [45]
The answer is P = 2(l+w) units.

This is because when you let the perimeter of the rectangle be P, the length of the rectangle be l and the width of the rectangle be w.

The information above can be expressed as the following equation,
P = 2l + 2w

You can then factorise out the common factor, 2.
P = 2(l+w)

Thus, the answer is P = 2(l+w) units.
3 0
3 years ago
Read 2 more answers
What is the next term in the sequence 7,12,17,22,...
Gnom [1K]
27
Because there is a common difference of 5 (it is an arithmetic sequence)
7 0
3 years ago
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How many variable terms are in the expression 3x^3y+5x^2-4y+z+9
Juliette [100K]

Answer:

5

Step-by-step explanation:

x + y + x + y + z = 5

5 0
3 years ago
PLSSS NEED HELP WILL GIVE CROWN
Mice21 [21]

Add :

-1.25 + 2.5 = <u>1.25</u>

For plotting the first one we first need to see the integer as here is 1 we will move to 1. Now, here it is given 0.25. Each line between 1 and 2 has 10 numbers gap so, as it 25 > 20 and 25 < 30. So, we should plot it between the 2nd and the 3rd line. As it is 5 it should be in between the line.

Refer the plotting for better identification

Add :

4.2 + (-0.4)

4.2 - 0.4

<u>3.8</u>

For plotting this one we will move to 3 than it has 8 < 10 so it should be plotted within the first dot.

Refer the attachment for better identification

7 0
3 years ago
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