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rjkz [21]
3 years ago
11

I'm working with varibles on both sides. This is math, also algebra 1. The expression is... 8-4a=16-8a I'm so confused on which

side to subtract from. I tried doing +8 on both sides. Please help.
Mathematics
2 answers:
LiRa [457]3 years ago
8 0
A=2, you add 8a to both sides and subtract 8 and then divide by 4
harkovskaia [24]3 years ago
3 0

Answer:

a=2

Step-by-step explanation:

You can have "a" on both sides and still get an answer easily. You start off by adding 8a to the right. That makes 8+4a=16. You then subtract 8 from 16 and get 4a=8. Divide by 4 to get your answer. You get a=2

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We are given:

\displaystyle \int \sqrt{x}\Big(9x^3-2\sqrt{x}+\frac{8}{x}\Big)\, dx

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Note that A is not valid. No integration property allows us to separate factors unless that factor is a constant.

We can simply rewrite and then distribute. First, by rewriting:

\displaystyle =\int x^{1/2}\Big(9x^3-2x^{1/2}+8x^{-1}\Big)\, dx

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