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MArishka [77]
3 years ago
5

App.nearpod.com X +6= 14 2.

Mathematics
1 answer:
djverab [1.8K]3 years ago
4 0
X=8 I’m not that to sure but hope i helped!
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Pls help meeeeeeeeeeeee
Solnce55 [7]

Answer:

A = 8

B = 6

C = 4

D = 7

Top = 29

Side = 20

Step-by-step explanation:

To get A on the bottom side row you divide 32 by 4 and get 8.

To get D, on the first side row, subtract A, 8, now it's 21, 21 divided by 3 is 7.

To get B, on the first top row, subtract A and D, now divide by 2 and you get 6.

To get C, on the third side row, subtract B and divide by 2 and you get 4.

4 0
2 years ago
Solve for the unknown. Rewrite each phrase as a multiplication sentence. Circle the scaling factor and put a box around the numb
skad [1K]
I hope this helps, i got it from a cheat sheet online

6 0
2 years ago
I’m taking a test right now and I had to rush so I wasn’t able to study please help..
Yakvenalex [24]

Answer:

86.13 I think? I scrath it I think its correct

7 0
2 years ago
Read 2 more answers
Use the given values of n and p to find the minimum usual value μ - 2σ and the maximum usual value μ + 2σ. Round your answer to
fenix001 [56]

Given Information:  

number of trials = n = 1042

Probability of success = p = 0.80

Required Information:  

Maximum usual value = μ + 2σ = ?

Minimum usual value = μ - 2σ = ?

Answer:

Maximum usual value = 859.51

Minimum usual value = 807.78

Step-by-step explanation:

In a binomial distribution, the mean μ is given by

μ = np

μ = 1042*0.80

μ = 833.6

The standard deviation is given by

σ = √np(1 - p)

σ = √1042*0.80(1 - 0.80)

σ = √833.6(0.20)

σ = 12.91

The Maximum and Minimum usual values are

μ + 2σ = 833.6 + 2*12.91

μ + 2σ = 833.6 + 25.82

μ + 2σ = 859.51

μ - 2σ = 833.6 - 25.82

μ - 2σ = 807.78

Therefore, the minimum usual value is 807.78 and maximum usual value is 859.51

8 0
3 years ago
Will give brainliest and more. 30 points. A cell phone company charges $40 plus $15 per line each month. Jake must spend less th
kolbaska11 [484]

they can have 5 cell phones.

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2 years ago
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