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4 years ago

Assume the least squares equation is ŷ = 10 + 20x. what does the value of 10 in the equation indicate?

1 answer:

3 0

10 is the initial value, found when x=0. I don't know what you are measuring by "0" and "10" here, so can't be more specific.

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The velocity of a particle moving back and forth on a line is vequalsStartFraction ds Over dt EndFraction equals6 sine (2 t )Sta

max2010maxim [7]

Answer:

s = 6 m

Step-by-step explanation:

The value of the velocity v is given as:

$v = \frac{ds}{dt} = 6 sin(2t)$ m/s

To find s, we have to integrate and apply the initial values of s = o when t = 0:

$\frac{ds}{dt} = 6 sin(2t)\\\\\int\limits^s_0 {ds} = \int\limits^t_0 {6sin(2t)} \, dt\\\\s|^s_o = -3cos(2t)|^t_o\\\\s - 0 = -3cos(2t) -(-3cos(0))\\\\s = -3cos(2t) + 3(1)\\\\s = -3cos(2t) + 3$

When t = π/2, s will be:

s = -3cos(2 * π/2) + 3

s = -3cos(π) + 3

s = -3(-1) + 3

s = 3 + 3

s = 6 m

4 0

3 years ago

You are playing a game in which you randomly select one square tile and one round tile from the sets shown below. Before you sel

AnnZ [28]

I think it is D
Hope my answer help you?

8 0

3 years ago

Read 2 more answers

A solution's temperature increased 11.3°C in 5 minutes. What was the average temperature increase per minute? Answer: _______ °C

sertanlavr [38]

Answer:

2.26° per minute

Step-by-step explanation:

11.3 / 5

7 0

3 years ago

I need answer asap pls help

MariettaO [177]

Answer: A= (3,-3) . B(4,1). C= (1,0)

Step-by-step explanation:

7 0

3 years ago

Can I get help please and thank you

Ipatiy [6.2K]

9514 1404 393

Answer:

a. 0.81

b. v = 28000(0.81^n)

c. 2757.36

Step-by-step explanation:

a. The growth factor is 1 more than the growth rate. Here, the growth rate is -19% (per year), so the growth factor, the multiplier, is ...

1 -0.19 = 0.81

b. The equation sets value equal to the original value multiplied by the growth factor to the power of the number of years:

value = (original value) × (growth factor)^n

v = 28000(0.81^n)

c. For n=11, this is ...

v = 28000(0.81^11) ≈ 2757.36

The value of the truck after 11 years is about $2757.

6 0

3 years ago