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guapka [62]
3 years ago
9

F(x) = -222 – 436 – 3x3 - 8?

Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
3 0
-1991 I think?????????
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The answer is Theta.

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Four functions are given below. Either the function is defined explicitly, or the entire graph of the function is shown.For each
Masja [62]

Summary of even and odd functions

A function f is even if the graph of f is symmetric with respect to the y-axis. Algebraically, f is even if and only if f(-x) = f(x) for all x in the domain of f.

A function f is odd if the graph of f is symmetric with respect to the origin. Algebraically, f is odd if and only if f(-x) = -f(x) for all x in the domain of f.

From the definition itself, we see how can we test if the functions are even or odd.

- First graph (to the left)

From the graph, we see that the function is symmetric with respect to the y-axis because the left side (x<0) is a reflection (along the y-axis) of the right side (x>0), so it is an even function.

- Second graph (to the right)

From the graph, we see that the function is symmetric with respect to the origin, the left side (x<0) is a reflection (along with the origin) of the side to the right (x>0), so it is an odd function.

- First function (to the left)

The function:

g(x)=5x^2

is an even function because we see that:

g(-x)=5\cdot(-x)^2=5x^2=g(x)

- Second function (to the right)

The function:

h(x)=-2x^5+3x^3

is an odd function because we see that:

h(-x)=-2\cdot(-x)^5+3\cdot(-x)^3=-(-2x^5+3x^3)=-h(x)^{}

Summary

We have the following results:

- First function (to the left): even

- Second graph (to the right): odd

- First function (to the left): even

- Second function (to the right): odd

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1 year ago
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If a well was 70-feet deep, the frog climbs 7 feet per hour, and it slips back 2 feet while resting? How long (in hours) will it
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Answer:

14 hours

Step-by-step explanation:

Given well is 70 ft deep.

Each step of the climb involves moving up at 7 ft/hr and then slips down 2 feet. Assuming the frog rests only once each hour, then the resultant progress made each hour,

= distance climbed - distance lost by slipping

= 7 - 2

= 5 ft / hr

Hence we can say that :

5 feet ---> takes 1 hour

1 foot ---> takes 1/5 hours

70 feet ---> takes (1/5) x 70= 14 hours

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