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nordsb [41]
3 years ago
14

Let f(x) = 3x + 5. Solve f−1(x) when x = 3

Mathematics
1 answer:
Gennadij [26K]3 years ago
8 0

Answer:

Step-by-step explanation:

The function f(x) is 3x+5

● (f-1)(x) = 3x+5 -1

● (f-1)(x) = 3x+4

Replace x with 3

● (f-1)(x) = 3×3+4 = 13

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What time is 5 1/ 2 hours after 7:00 pm?
irinina [24]

Answer:

12:30 a.m.

Step-by-step explanation:

You can automatically add 5 to the 7, 5 + 7 = 12. Then add 30 to the minuets. 00 + 30 = 30.

So, your answer is 12:30.

Hope this helps!!

8 0
3 years ago
Read 2 more answers
Dan recently bought a new mountain bike for $550. His friend works
Wittaler [7]
$990
550 x .80 = 440
$550 + $440 = $990
8 0
4 years ago
A candy store owner has chocolate candies worth $2.50 per pound and sour candies worth $0.90 per pound. How much of each kind of
SVETLANKA909090 [29]

Answer:

Weight of chocolate candies = 30lbs

Weight of sour candies = 30lbs

Step-by-step explanation:

We are told in the question that :

Chocolate candies worth $2.50 per pound

Sour candies worth $0.90 per pound. How much of each kind of candies should she combine to get 60 lb of mixed candies worth $1.70 per pound?

Let x represent the number of pounds of chocolate candies

Let 60 - x represent the number of pounds of sour candies

Hence, we have the equation

x × $2.50 + (60 - x) × $0.90 = 60 × $1.70

= 2.5x + 54 - 0.9x = 102

Collect like terms

2.5x - 0.9x = 102 - 54

= 1.6x = 48

x = 48/1.6

x = 30 lbs

x represent the number of pounds of chocolate candies,

60 - x represent the number of pounds of sour candies

= 60 - 30

= 30lbs

Weight of chocolate candies = 30lbs

Weight of sour candies = 30lbs

Therefore, she should combine 30lbs of chocolate candies and 30lbs of sour candies to get 60 lb of mixed candies worth $1.70 per pound.

4 0
3 years ago
What is the solution set?
Vikentia [17]
I think it was -15.75 if i rembmber
4 0
3 years ago
If a canoe travels with a speed of A mph for 3 hours, and then with a speed of B mph for the rest of the journey, how long does
Mandarinka [93]

Answer:

t = (C - 3*A)/B + 3

Step-by-step explanation:

Given in the question that,

the speed with which canoe travelled for first 3 hours = A

the speed with which he travelled for any and all time thereafter = B

As we do not know the values of A, B, or C, so the answer will be an expression for C in terms of A and B.

<h3>Formula to use</h3>

distance = speed x time

C = A*3 + B*(t-3)

Rearranging and solving for t

C - (A*3) = B*(t-3)

C - (A*3) = Bt - B3

C - (A*3) + B3 = Bt

t = C - (A*3) + B3 / B

or

t = (C - 3*A)/B + 3

4 0
3 years ago
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