Answer:
a) Percentage of students scored below 300 is 1.79%.
b) Score puts someone in the 90th percentile is 638.
Step-by-step explanation:
Given : Suppose a student's score on a standardize test to be a continuous random variable whose distribution follows the Normal curve.
(a) If the average test score is 510 with a standard deviation of 100 points.
To find : What percentage of students scored below 300 ?
Solution :
Mean
,
Standard deviation 
Sample mean 
Percentage of students scored below 300 is given by,






Percentage of students scored below 300 is 1.79%.
(b) What score puts someone in the 90th percentile?
90th percentile is such that,

Now, 






Score puts someone in the 90th percentile is 638.
5 times the quotient of 2 numbers is 5(r/t)
Answer is the third option
5(r/t)
Answer:
x = 7
Step-by-step explanation:
--> Triangle Similarity Theorem
120 = 8(3x - 6) --> Cross Multiplying
120 = 24x - 48 --> Distributing the 8
24x - 48 + 48 = 120 + 48 --> Adding 48 on both sides
24x = 168 --> Simplifying
24x/24 = 168/24 --> Divide 24 on both sides
x = 7 --> Simplifying
Hope this helped! <3
The simplification for this equation would be, 4x^2 y^26
Answer:
high jatdog
Step-by-step explanation:
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