Given,
3/3x + 1/(x + 4) = 10/7x
1/x + 1/(x+4) = 10/7x
Because the first term on LHS has 'x' in the denominator and the second term in the LHS has '(x + 4)' in the denominator. So to get a common denominator, multiply and divide the first term with '(x + 4)' and the second term with 'x' as shown below
{(1/x)(x + 4)/(x + 4)} + {(1/(x + 4))(x/x)} = 10/7x
{(1(x + 4))/(x(x + 4))} + {(1x)/(x(x + 4))} = 10/7x
Now the common denominator for both terms is (x(x + 4)); so combining the numerators, we get,
{1(x + 4) + 1x} / {x(x + 4)} = 10/7x
(x + 4 + 1x) / (x(x + 4)) = 10/7x
(2x + 4) / (x(x + 4)) = 10/7x
In order to have the same denominator for both LHS and RHS, multiply and divide the LHS by '7' and the RHS by '(x + 4)'
{(2x+4) / (x(x + 4))} (7 / 7) = (10 / 7x) {(x + 4) / (x + 4)}
(14x + 28) / (7x(x + 4)) = (10x + 40) / (7x(x + 4))
Now both LHS and RHS have the same denominator. These can be cancelled.
∴14x + 28 = 10x + 40
14x - 10x = 40 - 28
4x = 12
x = 12/4
∴x = 3
<h2>
Answer: y = ⁵/₂ x - 13 OR y + 8 =
⁵/₂ x - 5 </h2>
<h3>
Step-by-step explanation:</h3>
<u>Find the slope of the perpendicular line</u>
When two lines are perpendicular, the product of their slopes is -1. This means that the slopes are <em>negative-reciprocal</em>s of each other.
⇒ if the slope of this line = - ²/₅
then the slope of the perpendicular line (m) = ⁵/₂
<u>Determine the equation</u>
We can now use the point-slope form (y - y₁) = m(x - x₁)) to write the equation for this line:
⇒ y - (-8) = ⁵/₂ (x - 2)
∴ y + 8 = ⁵/₂ (x - 2)
We can also write the equation in the slope-intercept form by making y the subject of the equation and expanding the bracket to simplify:
since y + 8 = ⁵/₂ (x - 2)
y = ⁵/₂ x - 13
Answer:
(B) -1/5
Step-by-step explanation:
Answer:
-192
Step-by-step explanation:
3×[32-(4×4)×6]
3×[32-(16)×6]
3×[32-(96)]
3×(-64)
-192