An acid-base reaction or a neutralization reaction is a <u>chemical reaction that occurs between an acid and a base producing a salt and water</u>. The acids and bases can be strong or weak depending on their degree of ionization in water.
Butyric acid is a weak acid and in water it is ionized in the following way, loosing a proton (H+):
HC4H7O2 (aq) ⇆ H+ (aq) + C4H7O2- (aq)
On the other hand, potassium hydroxide is a strong base, so it will be completely ionized in water:
KOH(aq) → K+(aq) + OH-(aq)
Then the <u>net acid-base reaction</u> between butyric acid and KOH is:
HC4H7O2 (aq) + OH- (aq) ⇆ H2O + C4H7O2- (aq)
It is valid to consider only the OH- produced from the ionization of KOH in water since, as mentioned, this molecule is completely ionized. Also, we do not include the K + in the net equation since it is a spectator ion, it does not undergo chemical changes.
Explanation:
kclo3- 39+35.5+16*3=122.5
molar mass = 122.5
mass = 14.0g
volume= 100cm3
solubility in mol/dm3 or molarity = ?
but we know that
no of moles = solubility in mol/dm3×vol in cm3
---------------------------------------------
1000
no of moles = mass
---------
molar mass
mass\molar mass= solubility in mol/dm3 *vol in cm3/ 1000
14.0/122.5=x * 100/1000
solubility =0.875 mol/dm3
Answer:
I think that the volume will be 1.414
Explanation:
According to the formula of boyle's law P1 V1 = P2 V2
We have to find V2 so:
V2 = P2/P1 V1
By putting the values:
V2 = 5.06/2.11 * 1.696
V2 = 5.06/3.578
V2 = 1.414
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