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lakkis [162]
3 years ago
13

What are the 4 ways to find slope

Mathematics
1 answer:
slamgirl [31]3 years ago
4 0

Answer:

multiplying

Step-by-step explanation:

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Write these ratio in its simplest form 200:180​
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10:9

Step-by-step explanation:

4 0
3 years ago
Remi invests £600 for 5 years in a savings account.
Daniel [21]

Answer:

225600

Step-by-step explanation:

Simple interest formula:

A = P(1 + rt)

A = final amount

P = initial principal balance

r = annual interest rate

t = time (in years)

So...

A = 600(1 +(75 x 5) )

75 x 5 = 375

1 + 375 = 376

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A = 225600

6 0
3 years ago
HELP I NEED HELP ASAP
eimsori [14]

Answer:

I think its D

Step-by-step explanation:

You can rule out A and B because he would be able to throw it farther than 30 ft do that leaves C and D but davis Couldn't throw a 9.1 lb ball 30 ft so the answer is D

3 0
2 years ago
The concentration of particles in a suspension is 50 per mL. A 5 mL volume of the suspension is withdrawn. a. What is the probab
kolezko [41]

Answer:

(a) 0.6579

(b) 0.2961

(c) 0.3108

(d) 240

Step-by-step explanation:

The random variable <em>X</em> can be defined as the number of particles in a suspension.

The concentration of particles in a suspension is 50 per ml.

Then in 5 mL volume of the suspension the number of particles will be,

5 × 50 = 250.

The random variable <em>X</em> thus follows a Poisson distribution with parameter, <em>λ</em> = 250.

The Poisson distribution with parameter λ, can be approximated by the Normal distribution, when λ is large say λ > 10.  

The mean of the approximated distribution of X is:

μ = λ  = 250

The standard deviation of the approximated distribution of X is:

σ = √λ  = √250 = 15.8114

Thus, X\sim N(250, 250)

(a)

Compute the probability that the number of particles withdrawn will be between 235 and 265 as follows:

P(235

                             =P(-0.95

Thus, the value of P (235 < <em>X</em> < 265) = 0.6579.

(b)

Compute the probability that the average number of particles per mL in the withdrawn sample is between 48 and 52 as follows:

P(48

                             =P(-0.28

Thus, the value of P(48.

(c)

A 10 mL sample is withdrawn.

Compute the probability that the average number of particles per mL in the withdrawn sample is between 48 and 52 as follows:

P(48

                             =P(-0.40

Thus, the value of P(48.

(d)

Let the sample size be <em>n</em>.

P(48

                             0.95=P(-z

The value of <em>z</em> for this probability is,

<em>z</em> = 1.96

Compute the value of <em>n</em> as follows:

z=\frac{\bar X-\mu}{\sigma/\sqrt{n}}\\\\1.96=\frac{48-50}{15.8114/\sqrt{n}}\\\\n=[\frac{1.96\times 15.8114}{48-50}]^{2}\\\\n=240.1004\\\\n\approx 241

Thus, the sample selected must be of size 240.

5 0
3 years ago
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