Twice a first number decreased by a second number is 22. The first number increased by four times the second number is

There are two numbers that

Mumz [18]

Answer

20

Step-by-step explanation:

-4*20=-80

-4+20=16

5 0

3 years ago

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Please explain how i would figure out where to place it

pochemuha

Answer:

i cant see it wdym

Step-by-step explanation:

6 0

3 years ago

What is the area of the rectangle?

dedylja [7]

Answer:

22

Step-by-step explanation:

11 x 2 = 22

5 0

4 years ago

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Suppose we have a right triangle with legs of length a and b and hypotenuse of length c. Suppose b=3 and c=5. Then a= , For the

ANTONII [103]

Answer:

Length of right-angle triangle 'a' = 4

b)

$sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}$

$cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}$

$tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}$

Step-by-step explanation:

Step(i):-

Given b = 3 and hypotenuse c = 5

Given ΔABC is a right angle triangle

By using pythagoras theorem

c² = a² + b²

⇒ a² = c² - b²

⇒ a² = 5²-3²

=25 - 9

a² = 16

⇒ a = √16 = 4

The sides of right angle triangle a = 4 ,b = 3 and c = 5

Step(ii):-

$sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}$

$cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}$

$tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}$

7 0

3 years ago

A ball is thrown from an initial height of 4 feet with an initial upward velocity of 30 feet per second.

bonufazy [111]

Answer:

I guess that we want to find the position equation for the ball.

First, we know that any object that is in the air has acceleration equal to the gravitational acceleration (where we ignore forces like air resistance and others) so we can write the acceleration equation as:

a(t) = -32 ft/s^2

Where 32 ft/s^2 is the gravitational acceleration, and the negative sign is because this acceleration is downwards.

To get the velocity equation, we can integrate over time to get:

v(t) = (-32 ft/s^2)*t + v0

where v0 is the initial velocity.

We know that the ball is thrown upwards with a velocity of 30 ft/s, then:

v0 = 30ft/s

And the velocity equation becomes:

v(t) = (-32 ft/s^2)*t + 30 ft/s

Finally, for the position equation we need to integrate again, to get:

p(t) = (1/2)*(-32 ft/s^2)*t^2 + (30 ft/s)*t + p0

where p0 is the initial position.

We know that the ball is thrown from an initial height of 4 ft, then:

p0 = 4ft

Then the position equation (or height equation) of the ball is:

p(t) = (1/2)*(-32 ft/s^2)*t^2 + (30 ft/s)*t + 4 ft

5 0

3 years ago

Twice a first number decreased by a second number is 22. The first number increased by four times the second number is - 7.