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Veseljchak [2.6K]
3 years ago
13

Part A. Jose painted a square shaped mural. The length of each side of the canvas is 1 1/3 yards. What is the area of the mural

is square yards?
Part B. Lori painted a rectangular mural with the same area as Jose mural. Her mural is not square shaped.
What could be the demensions of Lori's mural, in yards?
Length=______ yards
Width=_______ yards
Mathematics
2 answers:
telo118 [61]3 years ago
7 0

Answer:

A). Area of mural = 1\frac{5}{9}\:yards^2

B). length = \frac{8}{9}\:yard

    width = 2 yards

Step-by-step explanation:

A).

Length of Side of Square shaped mural = 1\frac{1}{3}=\frac{4}{3}\:yards

Area of mural = side × side = \frac{4}{3}\times\frac{4}{3}

                       = \frac{16}{9}=1\frac{5}{9}\:yards^2

B).

Area of rectangular mural = \frac{16}{9}\:yards^2

Area of rectangle is given as = length × width

Means length and width can be any no whose product equals to \frac{16}{9}

one pair of such a number is as follows,

length = \frac{8}{9}\:yard

width = 2 yards

Pavel [41]3 years ago
4 0
A. Its a square. This means each side times the side would give us the area (s^2)
4/3^2 or 1.3333 x 1.33333 = 16 / 9 area.

B. Really just pick any numbers you want.
16 yards long and 1/9 wide.
As long as they multiply to 16/9
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enot [183]

Since g(h(x))=h(g(x))= x, hence functions h and g are inverses of each other

Given the functions expressed as:

h(x) =\sqrt{2x+2}\\g(x)\frac{x^2-2}{2}  \\

In order to check whether they are inverses of each other, we need to show that h(g(x)) = g(h(x))

Get the composite function h(g(x))

h(g(x))=h(\frac{x^2-2}{2} )\\h(g(x))=\sqrt{2(\frac{x^2-2}{2} )+2}\\h(g(x))=\sqrt{x^2-2+2} \\h(g(x))=\sqrt{x^2}\\h(g(x))=x

Get the composite function g(h(x))

g(h(x))=\frac{(\sqrt{2x+2} )^2-2}{2} \\g(h(x))=\frac{2x+2-2}{2}\\g(h(x))=\frac{2x}{2}\\g(h(x))=x

Since g(h(x))=h(g(x))= x, hence functions h and g are inverses of each other

Learn more on inverse functions here; brainly.com/question/14391067

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