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Veseljchak [2.6K]
3 years ago
13

Part A. Jose painted a square shaped mural. The length of each side of the canvas is 1 1/3 yards. What is the area of the mural

is square yards?
Part B. Lori painted a rectangular mural with the same area as Jose mural. Her mural is not square shaped.
What could be the demensions of Lori's mural, in yards?
Length=______ yards
Width=_______ yards
Mathematics
2 answers:
telo118 [61]3 years ago
7 0

Answer:

A). Area of mural = 1\frac{5}{9}\:yards^2

B). length = \frac{8}{9}\:yard

    width = 2 yards

Step-by-step explanation:

A).

Length of Side of Square shaped mural = 1\frac{1}{3}=\frac{4}{3}\:yards

Area of mural = side × side = \frac{4}{3}\times\frac{4}{3}

                       = \frac{16}{9}=1\frac{5}{9}\:yards^2

B).

Area of rectangular mural = \frac{16}{9}\:yards^2

Area of rectangle is given as = length × width

Means length and width can be any no whose product equals to \frac{16}{9}

one pair of such a number is as follows,

length = \frac{8}{9}\:yard

width = 2 yards

Pavel [41]3 years ago
4 0
A. Its a square. This means each side times the side would give us the area (s^2)
4/3^2 or 1.3333 x 1.33333 = 16 / 9 area.

B. Really just pick any numbers you want.
16 yards long and 1/9 wide.
As long as they multiply to 16/9
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The equation would be:

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Please help this is important for me.
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<h3>Answer: point Q is located at (-1, 1)</h3>

=================================================

Explanation:

Check out the diagram below.

Plot R(-3,7) and T(3,-11) on the same xy grid.

Draw a vertical line through R and a horizontal line through T. A right triangle forms. At the intersection point is point S(-3,-11)

----------------------

Now measure the distance from point S to point T. You can count out the spaces or subtract the x coordinates and use absolute value.

|x1-x2| = |-3-3| = |-6| = 6

From point S to point T is 6 units.

We want to subdivide this horizontal length in the ratio 1:2

What this means is that we want to plot a point U somewhere such that SU:UT = 1:2

In other words,

SU = x

UT = 2x

SU+UT = ST

x+2x = 6

3x = 6

x = 6/3

x = 2

So we must move 2 spaces to the right from point S to get to U(-1,-11)

Going from point U(-1,-11) to T(3,-11) is 4 spaces

We have SU:UT = 2:4 = 1:2 to help confirm we have the correct location for point U

From point U, we then move straight up to the line segment RT

We'll land on Q(-1,1)

----------------------

Another way to find the y coordinate of point Q is to subdivide the segment RS into the ratio 1:2 similar to how we divided ST up

Segment RS is 18 units long since we go from y = 7 to y = -11 when going from R to S.

If V was on segment RS such that

RV:VS = 1:2

and RV = y

then

RV+VS = RS

y+2y = 18

3y = 18

y = 6

RV = y = 6

VS = 2y = 2*6 = 12

So you'll move 6 units down from y = 7 to land on y = 1 (when going from the y coordinate of R to the y coordinate of Q)

3 0
3 years ago
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