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Veseljchak [2.6K]

3 years ago

13

Part A. Jose painted a square shaped mural. The length of each side of the canvas is 1 1/3 yards. What is the area of the mural

is square yards?
Part B. Lori painted a rectangular mural with the same area as Jose mural. Her mural is not square shaped.
What could be the demensions of Lori's mural, in yards?
Length=______ yards
Width=_______ yards

2 answers:

telo118 [61]3 years ago

7 0

Answer:

A). Area of mural = $1\frac{5}{9}\:yards^2$

B). length = $\frac{8}{9}\:yard$

width = 2 yards

Step-by-step explanation:

A).

Length of Side of Square shaped mural = $1\frac{1}{3}=\frac{4}{3}\:yards$

Area of mural = side × side = $\frac{4}{3}\times\frac{4}{3}$

= $\frac{16}{9}=1\frac{5}{9}\:yards^2$

B).

Area of rectangular mural = $\frac{16}{9}\:yards^2$

Area of rectangle is given as = length × width

Means length and width can be any no whose product equals to $\frac{16}{9}$

one pair of such a number is as follows,

length = $\frac{8}{9}\:yard$

width = 2 yards

Pavel [41]3 years ago

4 0

A. Its a square. This means each side times the side would give us the area (s^2)
4/3^2 or 1.3333 x 1.33333 = 16 / 9 area.

B. Really just pick any numbers you want.
16 yards long and 1/9 wide.
As long as they multiply to 16/9

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2 years ago

Tim Hortons is hiring and offers $200 every week plus $5 per hour. McDonalds offers $300 every week plus $2 per hour. State the

Bogdan [553]

Answer: After working for 33 $\frac{1}{3}$ hours a week

Step-by-step explanation:

Let us write equations to represent these two places. Let x be hours worked and y be money earned.

Tim Hortons:

$200 + $5x = y

McDonalds:

$300 + $2x = y

Now, to find the conditions of which Tim Hortons is the better employer (on the basis of money earned) we must find the interval that Tim Hortons pays more. This can be found by setting up another equation, or by graphing. I have shown both. <em>See attached for the graph</em>.

$200 + $5x > $300 + $2x

$5x > $100 + $2x

$3x > $100

x > $\frac{100}{3}$

x > 33.3334

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1 year ago

NarStor, a computer disk drive manufacturer, claims that the median time until failure for their hard drives is more than 14,400

Ne4ueva [31]

Answer:

The test statistics is $t = -1.727$

Step-by-step explanation:

From the question we are told that

The data given is

330 620 1870 2410 4620 6396 7822 81028309 12882 14419 16092 18384 20916 23812 25814

The population mean is $\mu = 14400$

The sample size is n = 16

The null hypothesis is $\mu \le 14400$

The alternative hypothesis is $H_a : \mu > 14400$

The sample mean is mathematically evaluated as

$\= x = \frac{\sum x_i}{n}$

So

$\= x = \frac{330+ 620+ 1870 +2410+ 4620+ 6396+ 7822+ 8102+8309+ 12882+ 14419+ 16092+ 18384 +20916+ 23812+ 25814 }{16}$

=> $\= x = 10799.9$

The standard deviation is mathematically represented as

$\sigma =\sqrt{\frac{ \sum (x_i - \=x)^2}{n}}$

So

$\sigma =\sqrt{\frac{(330- 10799.9)^2 + (620- 10799.9)^2+ (1870- 10799.9)^2 +(2410- 10799.9)^2 + (4620- 10799.9)^2 +(6396- 10799.9)^2 +(7822- 10799.9)^2 }{16}} \ ..$

$..\sqrt{ \frac{(8102 - 10799.9)^2 +(8309 - 10799.9)^2 + (12882 - 10799.9)^2 + (14419 - 10799.9)^2 + (16092 - 10799.9)^2 + (18384 - 10799.9)^2 +(20916 - 10799.9)^2 }{16}} \ ...$

$\ ... \sqrt{\frac{(23812 - 10799.9)^2 +(25814 - 10799.9)^2 }{16}}$

=> $\sigma = 8340$

Generally the test statistic is mathematically represented as

$t = \frac{10799.9- 14400}{ \frac{8340}{\sqrt{16} } }$

$t = -1.727$

From the z-table the p-value is

$p-value = P(Z > t) = P(Z > -1.727) = 0.95792$

From the values obtained we see that

$p-value > \alpha$ so we fail to reject the null hypothesis

Which implies that the claim of the NarStor is wrong

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