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Sati [7]
3 years ago
9

Two rival dry cleaners both advertise their prices. Store A’s prices are modeled by the expression 20x - 7, where x is the numbe

r of items brought in. Store B’s prices are modeled by the expression 4(5x + 7), where x is the number of items brought in. When do the two stores charge the same rate?
Mathematics
1 answer:
adelina 88 [10]3 years ago
6 0

Answer:

Step-by-step explanation:

Store A price is 20x-7

store B price is 4(5x+7)

Where x represents the number of items.

Now, observe that the coefficient of both expressions is 20, because 4(5x+7)=20x+7

Remember that the coefficient of the x-variable is always the constant rate of change. Also, the given expressions can be expressed as linear functions

y=20x-7

y=20x+28

Observe that both Stores have already the same rate, which is  20.

Therefore, they have the same rate at any number of items dry cleaned.

What they have different is their initial condition, -7 and +7 respectively, but the rate is the same..

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Lerok [7]
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King or Jack is mutually exclusive; they cannot both happen at the same time.
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King or Ace is mutually exclusive; they cannot both happen at the same time.
8 0
3 years ago
If you subtract a negative number from that same number you are taking a negative amount from the negative number you started wi
inn [45]

Answer:

Step-by-step explanation:

If u got two negative number such as (-6)+(-7) your answer will be positive 13.

If u got one negative number and one positive number like (-10)-(5) the answer will be negative like -5

7 0
3 years ago
Which value, when placed in the box, would result in a system of equations with infinitly many solutions? Y=2x - 5 2y-4x=
Nezavi [6.7K]

Given:

The system of equations is

y=2x-5

2y-4x=?

To find:

The missing value for which the given system of equations have infinitely many solutions.

Solution:

Let the missing value be k.

We have,

y=2x-5

2y-4x=k

Taking all the terms on the left side, the given equations can be rewritten as

-2x+y+5=0

-4x+2y-k=0

The system of equations a_1x+b_1y+c_1=0 and a_2x+b_2y+c_2=0 have infinitely many solutions if

\dfrac{a_1}{a_2}=\dfrac{b_1}{b_2}=\dfrac{c_1}{c_2}

We have,

a_1=-2,b_1=1,c_1=5

a_2=-4,b_2=2,c_2=-k

Now,

\dfrac{-2}{-4}=\dfrac{1}{2}=\dfrac{5}{-k}

\dfrac{1}{2}=\dfrac{1}{2}=\dfrac{5}{-k}

\dfrac{1}{2}=\dfrac{5}{-k}

On cross multiplication, we get

-k=10

k=-10

Therefore, the missing value is -10.

6 0
3 years ago
Suppose KLMN is a parallelogram, and that the bisectors of ∠K and ∠L meet at A. Prove that A is equidistant from LM and KN.
Neporo4naja [7]

Answer:

This is proved by ASA congruent rule.

 Step-by-step explanation:

Given KLMN is a parallelogram, and that the bisectors of ∠K and ∠L meet at A. we have to prove that A is equidistant from LM and KN i.e we have to prove that AP=AQ

we know that the diagonals of parallelogram bisect each other therefore the the bisectors of ∠K and ∠L must be the diagonals.

In ΔAPN and ΔAQL

∠PNA=∠ALQ    (∵alternate angles)  

AN=AL   (∵diagonals of parallelogram bisect each other)

∠PAN=∠LAQ      (∵vertically opposite angles)

∴ By ASA rule ΔAPN ≅ ΔAQL

Hence, by CPCT  i.e Corresponding parts of congruent triangles PA=AQ

Hence, A is equidistant from LM and KN.

7 0
3 years ago
HELP ME OUT GUYS!!!! Question is in the screenshot below.
Lostsunrise [7]
Im pretty sure it’s C. 9 times longer
4 0
3 years ago
Read 2 more answers
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