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2 years ago

What would this be subtracting decimals

Mathematics

1 answer:

andrew-mc [135]2 years ago

5 0

Answer: 6978.942

Step-by-step explanation: I added all of the terms up in a calculator and this is what I got! If you were looking to subtract them then it would equal -6948.142! The answer I got was based on the picture. Hope this helps!

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Emmanuel bought 28 lb of potting soil this week. This amount is 4 lb more than twice the amount of potting soil he bought last w

hammer [34]

He bought 60 pounds last week and p stands for 60

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3 years ago

I am struggling to figure out the last steps of this question:

igor_vitrenko [27]

I have attached a chart of the given information. Using subtraction from 100 and the other totals, you should be able to figure out the answer. If not, comment and I will send the completed chart

8 0

3 years ago

A parallelogram has a length of 15cm and a height of 7.5cm . Calculate it’s area (step by step)

poizon [28]

Answer:

Area of parallelogram is equal to $112.5cm^2$

Step-by-step explanation:

It is given length pf parallelogram which is equal to base of parallelogram is b=15 cm

Height of parallelogram h = 7.5 cm

We have to find the area of the parallelogram.

Area of parallelogram is equal to multiplication of base and height.

Therefore area of parallelogram is,

$A=bh$ , here b is base and h is height.

So $A=15\times 7.5=112.5cm^2$

Therefore area of parallelogram is equal to $112.5cm^2$

3 0

3 years ago

A flat circular plate has the shape of the region x squared plus y squared less than or equals 1.The plate, including the bound

rjkz [21]

Answer:

We have the coldest value of temperature $T(\frac{3}{4},0) = -9/16$ . and the hottest value is $T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$ .

Step-by-step explanation:

We need to take the derivative with respect of x and y, and equal to zero to find the local minimums.

The temperature equation is:

$T(x,y)=x^{2}+2y^{2}-\frac{3}{2}x$

Let's take the partials derivatives.

$T_{x}(x,y)=2x-\frac{3}{2}=0$

$T_{y}(x,y)=4y=0$

So, we can find the critical point (x,y) of T(x,y).

$2x-\frac{3}{2}=0$

$x=\frac{3}{4}$

$4y=0$

$y=0$

The critical point is (3/4,0) so the temperature at this point is: $T(\frac{3}{4},0)=(\frac{3}{4})^{2}+2(0)^{2}-(\frac{3}{2})(\frac{3}{4})$

$T(\frac{3}{4},0)=-\frac{9}{16}$

Now, we need to evaluate the boundary condition.

$x^{2}+y^{2}=1$

We can solve this equation for y and evaluate this value in the temperature.

$y=\pm \sqrt{1-x^{2}}$

$T(x,\sqrt{1-x^{2}})=x^{2}+2(1-x^{2})-\frac{3}{2}x$

$T(x,\sqrt{1-x^{2}})=-x^{2}-\frac{3}{2}x+2$

Now, let's find the critical point again, as we did above.

$T_{x}(x,\sqrt{1-x^{2}})=-2x-\frac{3}{2}=0$

$x=-\frac{3}{4}$

Evaluating T(x,y) at this point, we have:

$T(-(3/4),\sqrt{1-(-3/4)^{2}})=-(-\frac{3}{4})^{2}-\frac{3}{2}(-\frac{3}{4})+2$

$T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$

Now, we can see that at point (3/4,0) we have the coldest value of temperature $T(\frac{3}{4},0) = -9/16$ . On the other hand, at the point $-(3/4),\frac{\sqrt{7}}{4})$ we have the hottest value of temperature, it is $T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$ .

I hope it helps you!

4 0

2 years ago

Round to the nearest tenth if necessary. 60% of 68 is what number?..

galina1969 [7]

Answer:

40.8

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers