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Anastaziya [24]
3 years ago
13

Докажите тождество 3 n ( 3 m − 2 n ) + 6 m 2 = ( 6 m − 3 n ) ( 2 n + m ) .

Mathematics
1 answer:
valentina_108 [34]3 years ago
5 0

Answer:

The answer is 0

Step-by-step explanation:

3n(3m-2n) + 6m^2= (6m-3n)(2n+m)

By expansion

9mn - 6n^2 + 6m^2 = 12mn + 6m^2 -6n^2 - 3mn

By collecting like terms

9mn - 12mn + 3mn - 6n^2 + 6n^2 + 6m^2 - 6 m^2 = 0

-3mn + 3mn=0

Therefore the simplification of the expansion gives us 0

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Pls help if I don’t finish today mom will hurt me
kherson [118]

Answer:

We conclude that:

  • g(10) = 8

Step-by-step explanation:

First, we need to clear some concepts on how to fetch input and output from the function graph.

Determining the y-intercept:

We know that the y-intercept of the graph function can be determined by setting x = 0 and determining the corresponding y-value.

From the graph it is clear that x = 0, the value of y = 5. In other words, the graph intersects the y-axis at y = 5.

Therefore, the y-intercept of the graph is (0, 5).

Thus,

  • g(0) = 5

Determining the x-intercept:

We know that the x-intercept of the graph function can be determined by setting y = 0 and determining the corresponding x-value.

From the graph, it is clear that y = 0, the value of x = -10. In other words, the graph intersects the x-axis at x = -10.

Therefore, the x-intercept of the graph is (-10, 0).

Thus,

  • g(-10) = 0

Determining g(10):

From the graph, it is clearly visible that at x = 10, the value of the function output y = 8.

In other words,

  • at x = 10, g(10) = 8

Therefore, we conclude that:

  • g(10) = 8
5 0
3 years ago
Consider the initial value problem:
Inessa [10]

Answer:

\left \{ {{u'=v} \atop {v'=5v-6u-5\sin(2t)}} \right. \\u(0)=-5;u'(0)=2

Step-by-step explanation:

The given initial value problem is;

y''-5y'+6y=-5\sin(2t)---(1)\\y(0)=-5,y'(0)=2

Let

u(t)=y(t)----(2)\\v(t)=y'(t)----(3)

Differentiating both sides of equation (1) with respect to t, we obtain:

u'(t)=y'(t)---(4)\\ \\\implies u'(t)=v(t)---(5)

Differentiating both sides of equation (2) with respect to t gives:

v'(t)=y''(t)----(6)

From equation (1),

y''=5y'-6y-5\sin(2t)\\y''=5v(t)-6u(t)-5\sin(2t)\\\implies v'(t)=5v(t)-6u(t)-5\sin(2t)----(7)

Putting t=0 into equation (2) yields

u(0)=y(0)\\\implies u(0)=-5

Also putting t=0 into equation (3)

u'(0)=y'(0)\\u'(0)=2

The system of first order equations is:

\left \{ {{u'=v} \atop {v'=5v-6u-5\sin(2t)}} \right. \\u(0)=-5;u'(0)=2

3 0
3 years ago
Help plsssssssssssssssss
Helen [10]

Answer: A .0115

Step-by-step explanation:

There are 1000 mg in a gram. So to convert to grams, you would divide by 1000

8 0
3 years ago
Read 2 more answers
PLEASE HELP TIMED. Verify which of the following are identities.
Scrat [10]
A. both the equations are identities , i’m pretty sure
4 0
2 years ago
Graph the line that passes through the points (9,-8) and (9,6) and determine the
avanturin [10]

Answer:

<em>x = 9</em>

Step-by-step explanation:

The standard form of equation of a line is expressed as y = mx+c

m is the slope

c is the y intercept

Note that the line does not have a slope and the x intercept of the line is a point where the line cuts the x axis. Hence the equation of the line will be expressed as x = c where c is the x intercept;

<em>From the graph, the x intercept =9. Hence the equation of the given line is x = 9</em>

7 0
3 years ago
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