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coldgirl [10]
3 years ago
10

A triangle has sides with lengths of 7 feet, 15 feet, and 17 feet. is it a right triangle?

Mathematics
1 answer:
aksik [14]3 years ago
8 0
To test if this is a right triangle, let's test these side lengths with the Pythagorean Theorem.

a^2 + b^2 = c^2

c is the hypotenuse, the longest side of a right triangle.
a and b are the legs of the right triangle.

a = 7
b = 15
c = 17

7^2 + 15^2 = 17^2 ?

49 + 225 = 289 ?

274 ≠ 289

Thus, this triangle is not a right triangle since it does not satisfy the Pythagorean Theorem.

Have an awesome day! :)
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Solve algebraically. <br> 3x + y =3 <br> Y = 2x - 7
Annette [7]
<span>3x + y =3 
Y = 2x - 7

substitute </span>Y = 2x - 7 into  3x + y =3 
3x + y =3 
3x +2x - 7 =3 
5x = 10
x = 2

Y = 2x - 7 = 2(2) - 7 = -3

answer
(2, -3)


4 0
3 years ago
Read 2 more answers
A cyclist travels a distance of 837 1/2 feet in 25 seconds. The cyclist travels at a constant rate. What is the unit rate, in fe
wel

Answer:

\boxed{33.5 \ \text{feet/second}}

Step-by-step explanation:

To find the <u>unit rate,</u> we need to find out how much distance does the cyclist travel in 1 second. For that, we need to use the unitary method. A unitary method is a method that determines the unit rate of an object.

<u>Note:</u> Since the cyclist travels at a <u>constant rate</u>, unitary method can be used.

\rightarrow 837 \dfrac{1}{2}  \ \text{feet in 25 seconds}

\rightarrow 837.5 \ \text{feet} = 25 \  \text{seconds}

<u>Divide both sides by 25:</u>

\rightarrow \dfrac{837.5}{25} \ \text{feet} = \dfrac{25}{25}  \ \text{seconds}

\rightarrow 33.5 \ \text{feet} = 1  \ \text{seconds}

\rightarrow \boxed{33.5 \ \text{feet/second}}

Learn more about unitary method: brainly.com/question/19423643

3 0
3 years ago
Consider the system of equations.
jok3333 [9.3K]

Given:

The system of equations:

x-3y=9

\dfrac{1}{5}x-2y=-1

To find:

The number that can be multiplied by the second equation to eliminate the x-variable when the equations are added together.

Solution:

We have,

x-3y=9                        ...(i)

\dfrac{1}{5}x-2y=-1       ...(ii)

The coefficient of x in (i) and (ii) are 1 and \dfrac{1}{5} respectively.

To eliminate the variable x by adding the equations, we need the coefficients of x as the additive inverse of each other, i.e, a and -a So, a+(-a)=0.

It means, we have to convert \dfrac{1}{5} into -1. It is possible if we multiply the equation (ii) by -5.

On multiplying equation (ii) by -5, we get

-x+10y=5       ...(iii)

On adding (i) and (iii), we get

7y=14

Here, x is eliminated.

Therefore, the number -5 can be multiplied by the second equation to eliminate the x-variable.

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