Question

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Answer 1

The pressure : 1.536 atm

Further explanation

Same container=same volume⇒the volume is constant

Gay Lussac's Law  

When the volume is not changed, the gas pressure in the tube is proportional to its absolute temperature  

$\tt \dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}$

P₁=1 atm

T₁=20+273=293 K

T₂=450 K

the pressure :

$\tt P_2=\dfrac{P_1.T_2}{T_1}\\\\P_2=\dfrac{1\times 450}{293}=\boxed{\bold{1.536~atm}}$