A student compares the boiling point of substances having different intermolecular forces. <u>Boiling points of various substances</u> is the dependent variable that student most likely use.
<h3>Does the nature of intermolecular forces present in different substance affect their boiling points?</h3>
The boiling point of a substance is proportional to the strength of its intermolecular forces, the higher the boiling point, the stronger the intermolecular forces. We can compare the strengths of intermolecular forces by comparing the boiling points of different substances.
<h3>What properties are affected by intermolecular forces?</h3>
Intermolecular forces are measured by boiling points.
Intermolecular forces increase as bond polarization increases.
Ionic > hydrogen bonding > dipole dipole > dispersion is the order of the strength of intermolecular forces (and thus their impact on boiling points).
<h3>How can you determine strong and weak intermolecular forces?</h3>
Substances with strong intermolecular forces are very attracted to one another and are held together tightly. These substances require a great deal of energy to separate, whereas substances with weak intermolecular forces are held together very loosely and have weak interactions.
Learn more about intermolecular forces:
<u><em>brainly.com/question/13479228</em></u>
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Answer:
1) 18.91 mL
2) 2.35 %
Explanation:
1. The volume of base that was required is equal to the <em>difference between the reading at the end of the titration and the reading at the beginning</em>:
- V = 20.95 mL - 2.04 mL = 18.91 mL
2. The mass percent can be written as:
- Mass Percent = Mass solute / Total mass * 100%
For this problem:
We<u> input the data and calculate the mass percent</u>:
- % mass = 2.28/96.92 * 100% = 2.35 %
Answer:
C6H5COOH + OH- —> C6H5COO- + H2O
Explanation:
C6H5COOH + OH- —> C6H5COO- + H2O
In the reaction above, C6H5COOH donate a proton(H+) to form the carboxylate ion C6H5COO-. The proton (H+) combines with the OH- to form H2O.
This can better be understood in the illustration below
C6H5COOH + NaOH —> C6H5COONa + H2O
Answer:
1.61 x 10²⁰ molecules
Explanation:
Given parameters:
Mass of the hydrogen gas = 8.01 x 10⁻⁴g
Unknown
Number of molecules of NH₃ = ?
Solution:
Given reaction:
N₂ + 3H₂ → 2NH₃
We have to solve from the known to the unknown
- The known specie is the mass of H₂ ;
find the number of moles of the specie;
number of moles = 
Molar mass of H₂ = 2(1) = 2g/mol
Number of moles = 
= 0.0004mol
- 3 moles of H₂ will produce 2 moles of NH₃
0.0004 moles of H₂ will produce 
= 0.00027moles of NH₃
1 mole of a substance contains 6.02 x 10²³ molecules
0.00027mole of NH₃ will contain 0.00027 x 6.02 x 10²³
= 1.61 x 10²⁰ molecules
The entire woodpecker population would be DESTROYED
