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vladimir2022 [97]
3 years ago
5

Please please help!! and if you could show work too that would be amazing!!!

Mathematics
2 answers:
dimaraw [331]3 years ago
5 0
First you would add the two angles together to get 105. The. you do 180-105 to get 75. That is the missing angle. From there you would correspond the angles with the sides. Therefore the answer is Angle AB, angle BC, angle CA. these are in order from shortest to longest
Westkost [7]3 years ago
5 0

Answer:

AB, BC, AC

Step-by-step explanation:

Hi there,

In order to solve this problem, we should know that the longest side of the triangle is always opposite of the largest angle in a triangle. The first step is to find the angle measures. We are given the measures of ∠A and ∠C.

To find m∠B, just subtract the sum of the other angles and subtract the value from 180.

m∠A + m∠C + m∠B = 180°

65° + 40° + m∠B = 180°

105° + m∠B = 180°

m∠B = 75°

Now that we know all of the angle measures, we can identify the the lengths of the sides from least to greatest by looking at the angle value. <u>The greater the angle measure, the longer the opposite side would be. </u>

m∠A = 65° ⇒ opposite of side BC = medium side

m∠B = 75° ⇒ opposite of side AC = longest side

m∠C = 40° ⇒ opposite of side AB = shortest side

Hope this explanation helps. Cheers.

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Carl is on the school track team. To prepare for an upcoming race, he plans to run 207 miles total over the next 31 days. Write
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8 0
3 years ago
One day, thirteen babies are born at a hospital. assuming each baby has an equal chance of being a boy or girl, what is the prob
Nadya [2.5K]

Using the binomial distribution, there is a 0.9983 = 99.83% probability that at most eleven of the thirteen babies are girls.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

For this problem, the values of the parameters are:

p = 0.5, n = 13

The probability that at most eleven of the thirteen babies are girls is:

P(X \leq 11) = 1 - P(X > 11)

In which

P(X > 11) = P(X = 12) + P(X = 13)

Then:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 12) = C_{13,12}.(0.5)^{12}.(0.5)^{1} = 0.0016

P(X = 13) = C_{13,13}.(0.5)^{13}.(0.5)^{0} = 0.0001

So:

P(X > 11) = P(X = 12) + P(X = 13) = 0.0016 + 0.0001 = 0.0017

P(X \leq 11) = 1 - P(X > 11) = 1 - 0.0017 = 0.9983

0.9983 = 99.83% probability that at most eleven of the thirteen babies are girls.

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

8 0
2 years ago
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