Do you remember how to find the area of a circle ?
Big Fat Hint: The area of a circle is (pi) x (its radius)² .
Can you find the area of the big circle ... the one with radius = 18 m ?
Do that. The whole big circle, just as if there was nothing inside it, and
no shaded region.
I'll wait.
Now, can you find the area of the small circle ... the one with radius = 12 m ?
Do that.
I'll wait.
The area of the shaded region is just
(the area of the big circle) minus (the area of the small circle) !
I got 180 pi or roughly 565.2 m². I could be wrong. You should check it.
Domain is the x and range is y so your domain is 2,3,4,5 and your range is 0 and 4
Answer:
-85, -1.4, -0.9, 0.6, 14
Step-by-step explanation:
Answer:
Step-by-step explanation:
<u>Consider the parent function:</u>
The graph of the function open up and the vertex is at the origin, the point (0, 0)
Now, if it opens down, it means it is a reflection of the parent function over x axis, hence it has a negative coefficient, the function becomes:
The vertex is shifted to the point (-3, 0). It means the function also translated left by 3 units, the function becomes:
<u>Since all the options have 1/20 as a coefficient, our function is:</u>
This is option B
Answer: In particular, let’s focus our attention on the behavior of each graph at and around . 2 and x= -1 for x < 2. There are open circles at both endpoints (2, 1) and (-2, 1). The third is h (x) = 1 / (x-2)^2, in which the function curves asymptotically towards y=0 and x=2 in quadrants one and two."
Step-by-step explanation: I think this is the problem ur on
