Answer:
9
Step-by-step explanation:
you can always use guess-and-check:
124 seems rather high
(6)P(2) = 6!/4! = 6x5 ≠ 72
(9)P(2) = 9!/7! = 9x8 = 72
To take out terms outside the radical we need to divide the power of the term by the index of the radical; the quotient will be the power of the term outside the radical, and the remainder will be the power of the term inside the radical.
First, lets factor 8:
Now we can divide the power of the term, 3, by the index of the radical 2:
= 1 with a remainder of 1
Next, lets do the same for our second term
:
= 3 with a remainder of 1
Again, lets do the same for our third term
:
with no remainder, so this term will come out completely.
Finally, lets take our terms out of the radical:
We can conclude that the correct answer is the third one.
The value of the probability P(A and B) is 0.20
<h3>How to determine the
probability?</h3>
The given parameters about the probability are
P(A or B) = 0.9
P(A) = 0.5
P(B) = 0.6
To calculate the probability P(A and B), we use the following formula
P(A and B) = P(A) + P(B) - P(A or B)
Substitute the known values in the above equation
P(A and B) = 0.5 + 0.6 - 0.9
Evaluate the expression
P(A and B) = 0.2
Hence, the value of the probability P(A and B) is 0.20
Read more about probability at
brainly.com/question/25870256
#SPJ1
Find the mean,median,range of 6 6,8,5,4,6,4,3,8,4
SVEN [57.7K]
The numbers in order are
3, 4, 4, 4, 5, 6, 6, 6, 8
The median is the number in the middle, which is 5.
The range is the largest number minus the smallest number, 8 - 3 = 5
The mean is the sum of all the numbers divided by how many number are the in the list, 3 + 4 + 4 + 4 + 5 + 6 + 6 + 6 + 8 = 46, 46/9 = 5.11
Answer:
(2, -1)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtract Property of Equality
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
2x + y = 3
-2x + 5y = -9
<u>Step 2: Solve for </u><em><u>y</u></em>
<em>Elimination</em>
- Combine equations: 6y = -6
- Divide 6 on both sides: y = -1
<u>Step 3: Solve for </u><em><u>x</u></em>
- Define equation: 2x + y = 3
- Substitute in <em>y</em>: 2x - 1 = 3
- Isolate <em>y</em> term: 2x = 4
- Isolate <em>y</em>: x = 2
