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Svetradugi [14.3K]
3 years ago
9

6x -5у =15 x=y+3 x= t=

Mathematics
1 answer:
inessss [21]3 years ago
7 0

9514 1404 393

Answer:

  (x, y) = (0, -3)

Step-by-step explanation:

Using the second equation, we can substitute for x in the first equation:

  6(y+3) -5y = 15

  y +18 = 15 . . . . . collect terms

  y = -3 . . . . . . . . . subtract 18

Using the second equation:

  x = y +3 = (-3) +3 = 0

The solution is ...

  x = 0

  y = -3

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Answer:

The area of this circle is (\frac{\pi}{2} )  the area of the square.

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Step-by-step explanation:

Area of the circle is given by;

A_c = \frac{\pi d^2}{4}

Area of the square is given by;

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relationship between the edge length of the square, d, and length of its side, L,

d = \sqrt{L^2 + L^2} \\\\d = \sqrt{2L^2}

But area of the square , A_s = L^2

d = \sqrt{2A_s}

Then, the area of the square in terms of the edge length is given by;

A_s = \frac{d^2}{2}

Area of the circle in terms of area of the square is given by;

A_c = \frac{\pi d^2}{4} = \frac{\pi}{2}(\frac{d^2}{2} )\\\\But \ A_s = \frac{d^2}{2} \\\\A_c =  \frac{\pi}{2}(\frac{d^2}{2} )\\\\A_c =  \frac{\pi}{2}(A_s )

For the uniform electric field normal to the surface, the flux through the surface is electric field multiplied by the area of this surface.

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Flux through the surface of the circle is given by;

\phi _{circle} = E.(\frac{\pi d^2}{4})

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\phi _{square} = E.(\frac{d^2}{2} )\\\\\phi _{square} =E.(\frac{d^2}{2} ).(\frac{\pi}{2} ).(\frac{2}{\pi} )\\\\\phi _{square} =E.(\frac{\pi d^2}{4} ).(\frac{2}{\pi} )\\\\\phi _{square} =(\phi _{circle}).(\frac{2}{\pi} )

Therefore, Φsquare is (\frac{2}{\pi} ) ϕcircle

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