The answer to your question is 4x-12
Answer:
We have a + b as;
2 + 3 = 5
Step-by-step explanation:
Here, we want go get the value of a and b
from the second equation, we can get an expression for b
We have this as;
7a - b = 11
Thus,
b = 7a - 11
Now, from here, we can substitute the value of b into the first equation
We have this as;
5a + 4(7a - 11) = 22
5a + 28a -44 = 22
33a = 22 + 44
33a = 66
a = 66/33
a = 2
Recall;
b = 7a - 11
substituting the value of a from above;
b = 7(2) - 11
b = 14 - 11
b = 3
There will be 6 groups so we divide 27 by 6 which equals 4.5. soo each group will be getting 4. everyone would get atleast one with 3 left over.
Answer:
y = -x² + 6x - 1
General Formulas and Concepts:
<u>Algebra I</u>
- Standard Form: ax² + bx + c = 0
- Expanding by FOIL (First Inside Outside Last)
- Combining like terms
Step-by-step explanation:
<u>Step 1: Define equation</u>
y = -(x - 3)² + 8
<u>Step 2: Rewrite</u>
- Expand [FOIL]: y = -(x² - 6x + 9) + 8
- Distribute -1: y = -x² + 6x - 9 + 8
- Combine like terms: y = -x² + 6x - 1
Minus 12 over 16 and 12 over 16
There you go!
