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Amiraneli [1.4K]
2 years ago
13

Seth invested a certain amount of money and got back an amount of $ 8400. If

Mathematics
1 answer:
kupik [55]2 years ago
5 0

Answer:

$7700

Step-by-step explanation:

amount invested + interest = total

amount invested + 700 = 8400

Subtract 700 from both sides.

amount invested = 7700

Answer: $7700

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Angela bought gifts for her friends in each gift was $10 Y represent the total cost and X represent the number of guests right i
Nezavi [6.7K]

Answer:

each gift =$10

total=y

number of gifts =x

therefore,total= each gift * number of gifts

=$10* x

6 0
3 years ago
Find c, the hypotenuse, rounded to four decimal places, in a right triangle with b = 16 and B = 55°
vredina [299]
C is 19.5
I believe not promising
8 0
2 years ago
Read 2 more answers
Which ratio correctly compares 150 mm to 60 cm?
BartSMP [9]
Convert 150mm into cm = 15cm   
So 15cm to 60cm 
Divide by 15
B. 1 to 4
6 0
3 years ago
Find the equation for the circle with a diameter whose endpoints are (-5, -3) and (3,2).
densk [106]

Answer:

  (x +1)^2 +(y +0.5)^2 = 22.25

Step-by-step explanation:

The center of the circle is the midpoint of the diameter, so is ...

  (h, k) = ((-5, -3) +(3, 2))/2 = (-5+3, -3+2)/2 = (-1, -1/2)

The circle formula is then ...

  (x -h)^2 +(y -k)^2 = r^2

  (x -(-1))^2 +(y -(-1/2))^2 = r^2

We can find r^2 by substituting one of the points for (x, y).

  (3 +1)^2 +(2 +1/2)^2 = r^2 = 16 +6.25 = 22.25

Then the circle equation is ...

  (x +1)^2 +(y +0.5)^2 = 22.25

3 0
3 years ago
A ball is thrown in the air from a height of 3 m with an initial velocity of 12 m/s. To the nearest tenth of a second, how long
stepladder [879]

Answer:  1.4 seconds

<u>Step-by-step explanation:</u>

The equation is: h(t) = at² + v₀t + h₀          where

  • a is the acceleration (in this case it is gravity)
  • v₀ is the initial velocity
  • h₀ is the initial height

Given:  

  • a = -9.81 (if it wasn't given in your textbook, you can look it up)
  • v₀ = 12
  • h₀ = 3

Since we are trying to find out when it lands on the ground, h(t) = 0

EQUATION:   0 = 9.81t² + 12t + 3

Use the quadratic equation to find the x-intercepts

                        a=-9.81, b=12, c=3

x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}\\\\\\x=\dfrac{-(12)\pm \sqrt{(12)^2-4(-9.81)(3)}}{2(-9.81)}\\\\\\x=\dfrac{-12\pm 16.2}{-19.62}\\\\\\x=\dfrac{-12+ 16.2}{-19.62}=-0.2\qquad x=\dfrac{-12- 16.2}{-19.62}=\large\boxed{1.4}\\

Note: Negative time (-0.2) is not valid

4 0
3 years ago
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