All categories

3 years ago

What is the solution to the system of equations?

Mathematics

1 answer:

KonstantinChe [14]3 years ago

6 0

Answer:

(2,5)

Step-by-step explanation:

First, we notice that

y = -x + 7

y = 2x + 1

Next, since both -x + 7 and 2x + 1 are equal to y, than by that logic it means

-x+7 = 2x+ 1

Add x to both sides

7 = 3x+1

Subtract 1 from both sides

6 = 3x

x = 2

Now that we solved x, let's plug x = 2 into either -x+7 or 2x + 1. Either way, both will have the same answer.

y = -x + 7

y = -(2) +7

y = 5

Therefore, the answer is

x= 2

y = 5

(2,5)

You might be interested in

a cash register has $1.04 in coins. all the coins are pennies and dimes.there are 24 pennies in the cash register. Which represe

VladimirAG [237]

3-1 finds for she did to is to is to to fix l Fick

8 0

3 years ago

A time series that shows a recurring pattern over one year or less is said to follow a Select one:______

zaharov [31]

The answer is C. Seasonal pattern

3 0

3 years ago

Determine how long it will take for a principal amount of $13,000 to double its initial value when deposited into an account pay

bezimeni [28]

Compound interest can be defined as the interest <em>on a deposited amount, an investment</em> that is <em>compounded based on its principal and interest rate.</em>

It will take about 3.239 years for the principal amount of $13,000 to double its initial value.

From the above question, we can deduce that we are to find the time "t"

The formula to find the time "t" in compound interest is given as:

t = ln(A/P) / r

where:

P = Principal = $13,000

R = Interest rate = 21.4%

A = Accumulated or final amount

From the question, the Amount "A" is said to be the double of the principla.

Hence,

A = $13,000 x 2

= $26,000

Step 1: First, convert R as a percent to r as a decimal

r = R/100

r = 21.4/100

r = 0.214 per year.

Step 2: Solve the equation for t

t = ln(A/P) / r

t = ln(26,000.00/13,000.00) / 0.214

t = 3.239 years

Therefore, it will take about 3.239 years for the principal amount of $13,000 to double its initial value.

To learn more, visit the link below:

brainly.com/question/22471957

7 0

3 years ago

In a G.P the difference between the 1st and 5th term is 150, and the difference between the

liubo4ka [24]

Answer:

Either $\displaystyle \frac{-1522}{\sqrt{41}}$ (approximately $-238$ ) or $\displaystyle \frac{1522}{\sqrt{41}}$ (approximately $238$ .)

Step-by-step explanation:

Let $a$ denote the first term of this geometric series, and let $r$ denote the common ratio of this geometric series.

The first five terms of this series would be:

$a$ ,
$a\cdot r$ ,
$a \cdot r^2$ ,
$a \cdot r^3$ ,
$a \cdot r^4$ .

First equation:

$a\, r^4 - a = 150$ .

Second equation:

$a\, r^3 - a\, r = 48$ .

Rewrite and simplify the first equation.

$\begin{aligned}& a\, r^4 - a \\ &= a\, \left(r^4 - 1\right)\\ &= a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right) \end{aligned}$ .

Therefore, the first equation becomes:

$a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right) = 150$ ..

Similarly, rewrite and simplify the second equation:

$\begin{aligned}&a\, r^3 - a\, r\\ &= a\, \left( r^3 - r\right) \\ &= a\, r\, \left(r^2 - 1\right) \end{aligned}$ .

Therefore, the second equation becomes:

$a\, r\, \left(r^2 - 1\right) = 48$ .

Take the quotient between these two equations:

$\begin{aligned}\frac{a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right)}{a\cdot r\, \left(r^2 - 1\right)} = \frac{150}{48}\end{aligned}$ .

Simplify and solve for $r$ :

$\displaystyle \frac{r^2+ 1}{r} = \frac{25}{8}$ .

$8\, r^2 - 25\, r + 8 = 0$ .

Either $\displaystyle r = \frac{25 - 3\, \sqrt{41}}{16}$ or $\displaystyle r = \frac{25 + 3\, \sqrt{41}}{16}$ .

Assume that $\displaystyle r = \frac{25 - 3\, \sqrt{41}}{16}$ . Substitute back to either of the two original equations to show that $\displaystyle a = -\frac{497\, \sqrt{41}}{41} - 75$ .

Calculate the sum of the first five terms:

$\begin{aligned} &a + a\cdot r + a\cdot r^2 + a\cdot r^3 + a \cdot r^4\\ &= -\frac{1522\sqrt{41}}{41} \approx -238\end{aligned}$ .

Similarly, assume that $\displaystyle r = \frac{25 + 3\, \sqrt{41}}{16}$ . Substitute back to either of the two original equations to show that $\displaystyle a = \frac{497\, \sqrt{41}}{41} - 75$ .

Calculate the sum of the first five terms:

$\begin{aligned} &a + a\cdot r + a\cdot r^2 + a\cdot r^3 + a \cdot r^4\\ &= \frac{1522\sqrt{41}}{41} \approx 238\end{aligned}$ .

4 0

3 years ago

George spent 70 % of his saving to buy a camera. The camera cost $574 . How much did he originally have in savings?

viva [34]

574 : 70 * 100 =
820 $

5 0

3 years ago