Lets call those two unknown numbers a, b and write the info in the problem as equations:
a*b = 30
a + b = 40
lets solve for a in the second equation and substitute in the first:
<span>a + b = 40
</span>a = 40 - b
therefore:
<span>a*b = 30
</span>(40 - b)b = 30
40b - b^2 = 30
b^2 - 40b + 30 = 0
if we apply the general quadratic equation to solve we have:
b = (40 +- √(1600 - 120))/2
b = (40 +- √(1480<span>))/2
</span>b = (40 +- 38.47)/2
There are two solutions:
<span>b1 = (40 + 38.47)/2
</span><span>b1 = 39.24
b2 = (40 - 38.47)/2
</span>b2 = 0.765
lets use the second solution <span>b2 = 0.765, and substitute in the first equation to find a:
</span><span>a*b = 30
</span>a*0.765 = 30
a = 30/0.765
a = 39.216
so the numbers are 39.216 and 0.765
The greatest common factor is the biggest thing that they all share... If we look at it they all have 4 as their coefficients so you can take that out but they also have a squared so you can take that out too so the GCF if 4a squared... but No x because one of them doesn't have it... all of them have to have it in common.
Depends to what time (month, days, weeks) I'll assume annually which would be 150$ a year
Write as a system y= 2 x + 2.4x - 2y = 4
{y = 4
{2x + 2.4x - 2y = 4
Substitute the value of y into the equation
2x + 2.4x - 2 x 4 = 4
Solve the equation
x= 30/ 11
A possible solution is
(x, y) = (30/11, 4)
Check the solution
4 = 2 x 30/11+ 2.4 x 30/11 - 2 x 4 = 4
Simplify the expression
4 = 4 = 4
The ordered pair is a solution
(x, y) = ( 30/11, 4)
You do this by
3n+16=7n
-3n -3n
16=4n
divide each side by 4
16/4=4n/4
4=n
