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2 years ago

How can I get past Ambitious on my profile? I have 2000+ points, but the bar is still the same.

Mathematics

2 answers:

Naddika [18.5K]2 years ago

3 0

Answer:

You need to have Brainliest

Wewaii [24]2 years ago

3 0

Answer:

u dont exactly need 5 brainliest in next 30 days can do that or u can make ur paragraphs clear and consist

when ur answering

Step-by-step explanation:

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Marco picked answer A for the following problem. Why is that not the correct answer? (NO LINKS)

ICE Princess25 [194]

Answer:

This is not correct because the organic rice line in Graph A is increasing more than the conventional rice line. This is why the x- and y-labels are important: organic rice in Graph A; you are able to get more pounds for the same amount of weight. If organic rice costs more, you should get less pounds of rice. Graph B shows this relationship because the conventional rice line is higher than the orangic rice line, which indicates that you can get more conventional rice than organic rice at the same price, which is what the question says.

3 0

3 years ago

What is the perimeter of ^PQR with vertices P(-2,9) Q(7,-3) and R(-2,-3) in the coordinate plane?

e-lub [12.9K]

Using the distance formula we can determine the perimeter of PQR.

Distance formula: d=√(x-x1)^2+(y-y1)^2
distance of PR: √(-2+2)^2+(9+3)^2= 12
distance of QR: √(7+2)^2+(-3+3)^2=9
distance of PQ: √(7+2)^2+(-3-9)^2= 15

Perimeter: 12+9+15=36

5 0

3 years ago

Please help me solve this question. Will make you the

lawyer [7]

Yes because if you graph it, it will pass the vertical line test

4 0

3 years ago

PLEASE HELP!!!!

Lunna [17]

NOTES:

Given a quadratic function in standard format (y = ax² + bx + c), the direction of the parabola is as follows:

if "a" is positive, then opens UP
if "a" is negative, then opens DOWN

Given a quadratic function in standard format (y = ax² + bx + c), the vertex can be found as follows:

the Axis Of Symmetry (x-value) is: x = $\frac{-b}{2a}$
y-value is found by plugging in the AOS for "x" in the equation

****************************************************************************************

1) y = x² + 11x + 24

a = +1 so the parabola opens UP

x = $\frac{-b}{2a}$ = $\frac{-11}{2(1)}$ = $-\frac{11}{2}$

y = $(-\frac{11}{2})^{2}$ + 11 $(-\frac{11}{2} )$ + 24 = $-\frac{25}{4}$

vertex $(-\frac{11}{2}$ , $-\frac{25}{4})$ is in Quadrant 3 and is below the x-axis

This COULD be the graph of the rain gauge.

The graph should contain the vertex, x-intercepts (-3, 0) and (-8, 0), and y-intercept (0, 24)

******************************************************************************************

2) y = -x² - 6x - 8

a = -1 so the parabola opens DOWN

x = $\frac{-b}{2a}$ = $\frac{-(-6)}{2(-1)}$ = $\frac{6}{-2}$ = -3

y = -(-3)² - 6(-3) - 8 = -9 + 18 - 8 = 1

vertex (-3, 1) is in Quadrant 2 and is above the x-axis

This could NOT be the graph of the rain gauge.

The graph should contain the vertex, x-intercepts (-2, 0) and (-4, 0), and y-intercept (0, -8)

******************************************************************************************

3) y = x² - 2x + 3

a = 1 so the parabola opens UP

x = $\frac{-b}{2a}$ = $\frac{-(-2)}{2(1)}$ = $\frac{2}{2}$ = 1

y = (1)² - 2(1) + 3 = 1 - 2 + 3 = 2

vertex (1, 2) is in Quadrant 1 and is above the x-axis

This could NOT be the graph of the rain gauge.

The graph should contain the vertex, y-intercept (0, 3), and its mirror image (2, 3). <em>There are no x-intercepts</em>

******************************************************************************************

4) y = x² + 4x + 4

a = 1 so the parabola opens UP

x = $\frac{-b}{2a}$ = $\frac{-4}{2(1)}$ = -2

y = (-2)² + 4(-2) + 4 = 4 - 8 + 4 = 0

vertex (-2, 0) is in Quadrant 2 and is on the x-axis

This COULD be the graph of the rain gauge.

The graph should contain the vertex, y-intercept (0, 4), and its mirror image (-4, 4). <em>The x-intercept is the vertex.</em>

Compared to the other four graphs, this is most likely the equation for the rain gauge!

******************************************************************************************

5) y = 3x² + 21x + 30

a = +3 so the parabola opens UP

x = $\frac{-b}{2a}$ = $\frac{-21}{2(3)}$ = $-\frac{7}{2}$

y = 3 $(-\frac{7}{2})^{2}$ + 21 $(-\frac{7}{2} )$ + 30 = $-\frac{27}{4}$

vertex $(-\frac{7}{2}$ , $-\frac{27}{4})$ is in Quadrant 3 and is below the x-axis

This COULD be the graph of the rain gauge.

The graph should contain the vertex, x-intercepts (-2, 0) and (-5, 0), and y-intercept (0, 30)

*******************************************************************************************

4 0

3 years ago

Read 2 more answers

Suppose 6 quarts of a solution that is 52% antifreeze is mixed with 10 quarts of a solution that is 32% antifreeze. (A) how many

Vadim26 [7]

The total amount of the resulting mixture can be calculated by adding up the volume of the given substances assuming that volume addition is applicable given the properties of the fluids used.

That is,
T = 6 quarts + 10 quarts = 16 quarts

The total volume of the resulting mixture is 16.

Then, we do the component (antifreeze) balance by adding up the resulting antifreeze from the substances to the total. We let x be the percentage of antifreeze in the final mixture.

6(0.52) + 10(0.32) = 16(x)

The value of x from the equation is 0.395.

Therefore, the answer to this item is 39.5%.

4 0

3 years ago