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IgorC [24]
2 years ago
10

Under a dilation, the point (2, 6) is moved to (6, 18).

Mathematics
1 answer:
Sergio039 [100]2 years ago
4 0

Answer:

3

Step-by-step explanation:

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The sum of (-12) and (5) is<br><br> (A) 6 (B) 8 (C) -7
ella [17]

Answer:

-7

Step-by-step explanation:

-12 +5

Since the signs are different

Take the larger number and subtract the smaller number

12-5 =7

Take the sign of the larger

-7

5 0
2 years ago
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if emma spent $14.00 on jewerly and recieved $6.00 in change how much money did she spent . what equation could be used to find
rjkz [21]
14.00-6.00=8.00 if the cashier gave her 6.00 then she spent at least 8.00
7 0
2 years ago
How do I convert 1 5/6 into a decimal??????
zavuch27 [327]

Answer:

1.8(3) (three is a repeating number)

Step-by-step explanation:

Divide the numerator from the denominator. Add the value of the integer part.

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2 years ago
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First time on Brainly! Please Help!!!!! &gt;^&lt;
lys-0071 [83]
Welcome to Brainly!

Binomial Theorem will follow this pattern:
The powers start at 3 and decrease down to 0 for the first term,
and start at 0 and increase to 3 for the other term.

(2x+4)^3 =

\rm \_\_(2x)^34^0+\_\_(2x)^24^1+\_\_(2x)^14^2+\_\_(2x)^04^3

See how the power counts down on the (2x)
and counts up on the 4?
That's the pattern that our expansion must follow.

I left a little space in front of each term.
The coefficient in front of each term will come from the fourth row of Pascal's Triangle. The one that looks like this:

1 3 3 1

Those are the coefficients we want:

\rm 1(2x)^34^0+3(2x)^24^1+3(2x)^14^2+1(2x)^04^3

We can clean this up a little bit by getting rid of some of the junk. Anything to the 0th power is 1. So let's suppress all of our 1's because multiplying by 1 is not important.

\rm (2x)^3+3(2x)^24+3(2x)4^2+4^3

Now apply exponent rule, distributing the power to both the 2 and the x where applicable.

\rm 2^3x^3+3\cdot2^2x^24+3\cdot2x4^2+4^3

Remember, multiplication is COMMUTATIVE, meaning we can multiply things in any order. So let's bring the numerical portion to the front of each term and multiply it all out.

\rm 2^3x^3+3\cdot2^2\cdot4x^2+3\cdot2\cdot4^2x+4^3
\rm 8x^3+48x^2+96x+64
6 0
3 years ago
Given your sister's incomplete text,
yaroslaw [1]
We automatically know the coordinate point is in quadrant 2 or 3 without knowing the y value because every point with a negative x value lands in those squadrants.
8 0
3 years ago
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