No the corresponding angles are not congruent, because the angle measures on the smaller figure are 90, 90, 137, and 43, while the larger figure has angle measures of 90, 90, 136, 44. that is why the following figures are not congruent.
ANSWER
Possible rational roots: <span><span>±1,±2,±3,±4,±6,±12</span><span>±1,±2,±3,±4,±6,±12</span></span>
Actual rational roots: <span><span>1,−1,2,−2,−3</span></span>
<span><span>see attachments for all steps.</span></span>
Answer:
(f•g)(4) = 45
Step-by-step explanation:
f(x)=4x+1
g(x)=x^2-5
(f•g)(x) = 4(x^2 -5)+1
(f•g)(4) = 4(4^2 -5)+1
(f•g)(4) = 4(16-5)+1
(f•g)(4) = 4(11)+1
(f•g)(4) = 44 + 1
(f•g)(4) = 45
3.70+1.25+1.48= 6.43.
20-6.43=13.57
You would get $13.57
Answer:
Step-by-step explanation:
Given a general quadratic formula given as ax²bx+c = 0
To generate the general formula to solve the quadratic equation, we can use the completing the square method as shown;
Step 1:
Bringing c to the other side
ax²+bx = -c
Dividing through by coefficient of x² which is 'a' will give:
x²+(b/a)x = -c/a
- Completing the square at the left hand side of the equation by adding the square of half the coefficient x i.e (b/2a)² and adding it to both sides of the equation we have:
x²+(b/a)x+(b/2a)² = -c/a+(b/2a)²
(x+b/2a)² = -c/a+(b/2a)²
(x+b/2a)² = -c/a + b²/4a²
- Taking the square root of both sides
√(x+b/2a)² = ±√-c/a + b²/√4a²
x+b/2a = ±√(-4ac+b²)/√4a²
x+b/2a =±√b²-4ac/2a
- Taking b/2a to the other side
x = -b/2a±√√b²-4ac/2a
Taking the LCM:
x = {-b±√b²-4ac}/2a
This gives the vertex form with how it is used to Solve a quadratic equation.
