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Ann [662]
3 years ago
11

Given f(x) = 19x + 12 , find f(3) F(3)= ?

Mathematics
2 answers:
Keith_Richards [23]3 years ago
6 0

Answer:

f ( 3 ) = 69

Step-by-step explanation:

Given :-

f ( x ) = 19x + 12.

To find :- f ( 3 ) = ?

<u>Solution :- </u>

f ( x ) = 19x + 12.

Substitute as the 3 as x

f ( 3 ) = <u>19 ( 3 )</u> + 12

Multiply ; 19 × 3

f ( 3 ) = 57 + 12

Add 57 and 12

f ( 3 ) = 69

amm18123 years ago
4 0

Answer:

69

Step-by-step explanation:

to find f(3), we'll have to substitute x with 3

therefore,

f(3) = 19 × 3 + 12

= 57 + 12

= 69

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Given the function, g(x)=5x^5/x^3-2x+1, choose the correct horizontal asymptote. none y = 0 y = 1 y = 3
viktelen [127]

Answer:  NONE

<u>Step-by-step explanation:</u>

Consider that m is the degree of the numerator and n is the degree of the denominator.

The rules for horizontal asymptote (H.A.) are as follows:

If m > n   then no H.A. (use long division to find the slant asymptote)

If m = n   then H.A. is y = leading coefficient of numerator/leading coefficient of denominator

If m < n   then H.A. is y = 0

Given: g(x) = 5x⁵/(x³ - 2x + 1)

--> m = 5, n = 3

Since m > n then there is no H.A.

8 0
3 years ago
Find the circumference of a circle that has a 25-inch radius. Use 3.14 to approximate π.
Sergio [31]

\huge \tt \color{pink}{A}\color{blue}{n}\color{red}{s}\color{green}{w}\color{grey}{e}\color{purple}{r }

\large\underline{  \boxed{ \sf{✰\:Important\: point's }}}

  • ➣ Circle:- A two-dimensional geometric figure, a line, consisting of the set of all those points in a plane that are equally distant from a given point (center).
  • ➣ Circumference:- The line that bounds a circle or other two-dimensional figure

{ \rule{70mm}{2.9pt}}

★ also circumference of a circle is also known as it's perimeter

  • ➣To find circumference of circle when use formula

{ \boxed{✜\underline{  \boxed{ \sf{\: Circumference \:  of  \: circle= \: 2\pi \: r}}}✜}}

  • ➢ r = radius (25inch.)
  • ➢ value of π is 3.14

{ \rule{70mm}{2.9pt}}

\large\underline{  \boxed{ \sf{✰\: Let's\:solve }}}

\sf{➛ \: Circumference  \: of  \: circle = 2 \times 3.14 \times 25} \\ \sf{➛ \: Circumference  \: of  \: circle =2 \times 78.5} \\ \sf{➛ \: Circumference  \: of  \: circle =157inch}

★ Hence circumference of circle=157inch

\large\underline{  \boxed{ \sf{➪\:157inch. }}}

{ \rule{70mm}{2.9pt}}

Hope it helps !

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