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STALIN [3.7K]
4 years ago
13

Max said that he and Gwen cannot equally share $7.40 because 5 one-dollar bills cannot be divided into two groups. Is Max correc

t?
Mathematics
2 answers:
Sonbull [250]4 years ago
8 0
He is correct about the dollar bills, but you can split 7.40$ equally
shusha [124]4 years ago
3 0
Nein, he is wrong, if it was with the dollar bills only, then sure, you can't, but $7.40 / 2 is $3.70, so they would be able to share it equally
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Ok guys i need some help
Strike441 [17]
Hello!

The surface area is the area of all of the shapes on the net added up. First we will find the area of the two triangles.

A=0.5bh
A=0.5(3·6)
A=0.5(18)
A=9

Since there are two triangles we double this area, giving us 18.

Now let's find the length of the two side rectangles.

7(4)=28
28+28=56

Now to find the middle rectangle.

6(7)=42

Now we add up all of the area to find the surface area.

42+56+18=116

The surface area is 116 cm².

I hope this helps!
5 0
3 years ago
Last one i need help with to move on! I have a pic of the question
adoni [48]

length = 4 yards and width = 3.5 yards

let width be w then length is 2w - 3

area = w(2w - 3) = 14 (rearrange in standard form )

2w² - 3w - 14 = 0 ← in standard form

(2w - 7 )(w + 2 ) = 0 ← in factored form

equate each factor to zero and solve for w

2w - 7 = 0 ⇒ w = 3.5

w + 2 = 0 ⇒ w = - 2

but w > 0, hence w = 3.5

width = 3.5 yards and length = (2 × 3.5 ) - 3 = 4 yards


8 0
3 years ago
Compute (1+i)(1+2i)(1+3i).
Maslowich

Answer:

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Step-by-step explanation:


3 0
4 years ago
Jeanette can swim 45 meters in 30 seconds. How far can she probably swim in 90 seconds?
shtirl [24]
H. 135 meters

Work: 45 meters in 30 seconds 45/30= 1.5 so 90x1.5 = 135 meters
6 0
3 years ago
Read 2 more answers
Evaluate the integral x^3 (x 4 −8)^44 dx by making the substitution u = x^4 - 8
Eduardwww [97]

Answer:

(x^4-8)^45 /180 +c

Step-by-step explanation:

If u=x^4-8, then du=(4x^3-0)dx or du=4x^3 dx by power and constant rule.

If du=4x^3 dx, then du/4=x^3 dx. I just divided both sides by 4.

Now we are ready to make substitutions into our integral.

Int(x^3 (x^4-8)^44 dx)

Int(((x^4-8)^44 x^3 dx)

Int(u^44 du/4)

1/4 Int(u^44 dul

1/4 × (u^45 / 45 )+c

Put back in terms of x:

1/4 × (x^4-8)^45/45 +c

We could multiply those fractions

(x^4-8)^45 /180 +c

5 0
3 years ago
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