Yes, because the data can be displayed by a relative frequency compared with the whole.
It would be a parallelogram
From the given description it seems that the small shaded circle lies within the larger circle as shown in image below:
The probability that a point choosen at random lies within the shaded area = Area of shaded region / Total area of the bigger cricle
So,
Probability = 78.5/314 = 0.25
Thus there is 0.25 or 25% probability that the point chosen at random will lie inside the shaded region.
(y-4) (y-3)
you look at 12 and see what two factors of 12 add up to -7 and -4 times -3 is 12 and -4+-3 = -7