recall that for inverse functions, <u>the range of the original is the domain of the inverse</u> and othe other way around.
so f⁻¹(8) is f⁻¹(x) but making x = 8, so the domain value in this case for the inverse is 8, and that's going to give us something, but let's nevermind that.
since the domain value is 8 for the inverse, that means, the same 8, is a range for the original f(x).
meaning, "some value of x" on the original, gives us a range of 8, then let's use that 8 in the original, BUT not on "x", but on "y", or f(x).
so notice how the values swap places for the inverses, one's domain, is the other's range.