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ladessa [460]
3 years ago
9

If the y-intercept of your quadratic is (0,5) and your axis of symmetry is x=4,

Mathematics
1 answer:
Free_Kalibri [48]3 years ago
4 0

The axis of symmetry goes through the x-value. 4. So your equation for your axis of symmetry is going to be x equals. 0 (undetermined)

- branliest will be appreciated

Thanks

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The length of a rectangle is 3 centimeters less than four times its width. Its area is 10 square centimeters. Find the dimension
Kay [80]

Answer:

W = 2 cm

L = 5 cm

Step-by-step explanation:

A rectangle is a four sided shape with 4 perpendicular angles. It has two pairs of parallel sides which are equal in distance: width and length. Its area, the amount of space inside it, can be found using the formula A = l*w. If the area is 10 cm² and the length is "3 cm less than 4 times the width" or 4w - 3, you can substitute and solve for w.

A = l*w

10 = (4w - 3)(w)

10 = 4w² - 3w

Subtract 10 from both sides to make the equation equal to 0. Then solve the quadratic by quadratic formula.

4w² - 3w - 10 = 0

Substitute a = 4, b = -3 and c = -10.

w = \frac{3 +/- \sqrt{(-3)^2 - 4(4)(-10)} }{2(4)} = \frac{3 +/- \sqrt{9 +160)} }{8} =  \frac{3 +/- \sqrt{169} }{8} = \frac{3+/-13}{8}

There are two possible solutions which can be found.

3 + 13 / 8 = 16/ 8 = 2

3 - 13 / 8 = -10/8 = -5/4

Since w is a side length or distance, it must be positive so w = 2 cm.

If the width is 2 cm then the length is 4(2) - 3 = 8 - 3 = 5 cm.

8 0
3 years ago
Graph the inequality 4x -2y < 8
iris [78.8K]

Mine is pretty rough but hope it helps look at the attached image.

8 0
4 years ago
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NeX [460]
X-3=66
x=69

69+41+(y-9)=180
110+y-9=180
101+y=180
y=79
7 0
3 years ago
I Have 10 Minutes Hurry for Brainlist and pls be accurate
yulyashka [42]

To find the equation we will put the values of x and y in the equations and then check if LHS=RHS.

\large\red{\sf{y=3x-1}}

  • x=1
  • y=9

\begin{gathered}\\ \sf\longmapsto 9=3(1)-1\end{gathered}

\begin{gathered}\\ \sf\longmapsto 9=3-1\end{gathered}

\begin{gathered}\\ \sf\longmapsto 9≠2 \end{gathered}

\large\green{\sf{y=5x+4}}

\begin{gathered}\\ \sf\longmapsto 9=5(1)+4\end{gathered}

\begin{gathered}\\ \sf\longmapsto 9=5+4\end{gathered}

\begin{gathered}\\ \sf\longmapsto 9=9\end{gathered}

\large\blue{\sf{y=-2x-8}}

\begin{gathered}\\ \sf\longmapsto 9=-2(1)-8\end{gathered}

\begin{gathered}\\ \sf\longmapsto 9=-2-8\end{gathered}

\begin{gathered}\\ \sf\longmapsto 9≠10\end{gathered}

\large\pink{\sf{y=6x-8}}

\begin{gathered}\\ \sf\longmapsto 9=6(1)-8\end{gathered}

\begin{gathered}\\ \sf\longmapsto 9=6-8\end{gathered}

\begin{gathered}\\ \sf\longmapsto 9≠-2\end{gathered}

Hence, Option B. y=5x+4 satisfies the system (1,9)

7 0
3 years ago
5 times 5 grggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggrfgrrrrrrrrrrrrrrrrrrrrrrr
Bezzdna [24]

Answer:

25

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
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