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Answer:
Direct Mapped Cache
Explanation:
Given that a Direct Mapped Cache is a form of mapping whereby each main memory address is mapped into precisely one cache block.
It is considered cheaper compared to the associative method of cache mapping, and it is faster when searching through it. This is because it utilizes a tag field only.
Hence, The method of mapping where each memory location is mapped to exactly one location in the cache is "Direct Mapped Cache"
Programs are series of instructions interpreted by a computer
- The description of the program is to compute the square of the difference between corresponding elements of two arrays
- The better version of the program is program A.
<h3>How to describe the programs</h3>
From the programs, we have the following highlights
- The program iterates from 1 to n - 1
- The iteration calculates the difference between corresponding elements of the arrays
- The difference is then squared
Hence, the description of the program is to compute the square of the difference between corresponding elements of two arrays
<h3>The better version</h3>
The better version of the program is program A.
This is so, because the program uses fewer instructions for the same task as program B
Read more about programs at:
brainly.com/question/16397886
Answer:
(a) The algorithm is as follows:
count = 0
for i = 1 to n:
if x = xi:
count++
print(count)
(b) n comparisons
Explanation:
Solving (a):
Assume the integer to locate is x and the elements of the list are: 
Such that: 
The algorithm is as follows:
<em>count = 0</em>
<em>for i = 1 to n:</em>
<em> if x = xi:</em>
<em> count++</em>
<em>print(count)</em>
<em />
The above iterates through the count of the list (i.e. n) and makes comparison with each element of the list (i.e. element 1 to element n).
When a match is found, the count variable is incremented by 1 and printed at the end of the loop
Furthermore:
If there are 3 elements in the list, the algorithm makes 3 comparisons.
It makes 10 comparisons if there are 10 elements in the list.
<em>So: it makes n elements if there are n elements in the list</em>
Int main(void){
int n,s=0;
while(1){
scanf(" %d",&n);
if(n<0) break;
s+=n;
}
printf("sum=%d\n",s);
return 0;
}
