This question is incomplete, the complete question is;
Flag
A constant force F = 6i+8j-6k moves an object along a straight line from point (6, 0, -10) to point (-6, 7, 2).
Find the work done if the distance is measured in meters and the magnitude of the force is measured in newtons.
Answer:
the work done is -88 J
Explanation:
Given the data in the question;
we know that;
Work done = F × S
where constant force F = ( 6i + 8j - 6k )
S = ( -6i + 7j + 2k ) - ( 6i + 0j - 10k )
S = ( (-6i - 6i) + (7j - 0j) + ( 2k - ( -10k) ) )
S = ( -12I + 7j + 12k )
so
Work force = ( 6i + 8j - 6k ) × ( -12I + 7j + 12k )
Work force = ( 6 × -12 ) + ( 8 × 7 ) + ( -6 × 12 )
Work force = -72 + 56 - 72
Work force = -88 J
Therefore, the work done is -88 J
Answer:

Explanation:
Given equation:

To solve the given equation:


Multiply both sides by T₀:

Add 100 to both sides:

Subtract
from both sides:

Factor out the common term T₀:

Divide both sides by 

Carry out the calculation:



It really doesn't matter whether it's a compression wave in a Slinky®,
or a trained frog, or a model airplane, or a baby chicken.
Time = distance / speed
Time = (9 m) / (2 m/s) = 4.5 seconds
Answer:
The answer is 2,500 * 45 = 112500kgm/s
Yes the root is made up of 3 layers. Henle's layer,<span> Huxley's layer, and the cuticle.
</span>