Answer: 1960 joules
Explanation:
Given that:
Mass of barbell = 200-kg
Height = 1 meter
Work done by weightlifter = ?
Recall work is done when force is applied on an object over a distance.
i.e Workdone = Force X Distance h
(Since force = Mass m x gravitational acceleration g)
Workdone = mgh
= 200kg x 9.8ms^2 x 1m
= 1960 joules
Thus, 1960 joules of work is performed by the weightlifter.
Answer:
Option A (1.51 m) is the appropriate option.
Explanation:
The given values are:
Speed of wave,
= 362 m/s
Period,
= 4.17
Now,
⇒ 
then,
⇒ 
⇒ 
⇒ 
Answer:
Revisar las respuestas a cada problema, como se muestra mas adelante.
Explanation:
Para poder solucionar esta serie de problemas debemos de utilizar la segunda ley de Newton, la cual nos dice que la sumatoria de fuerzas sobre un cuerpo debe de ser igual producto de la masa por la aceleracion.
De esta manera tenemos:
ΣF = m*a
donde:
F = fuerza [N]
m = masa [kg]
a = aceleracion [m/s^2]
1 )
F = m*a
60 = m*4
m = 15[kg]
2)
F = m*a
a = 250/50
a = 5 [m/s^2]
3)
F = m*a
F = 80*2.5
F = 200 [N]
4)
F = m*a
800 = 1500*a
a = 0.533[m/s^2]
5)
F = m*a
100 = 500*a
a = 100/500
a = 0.2 [m/s^2]
the action and reaction do not lead equilibrium if action and reaction force react on different objects
