If f(x) = 1 - 2x^3, find the inverse of f.

1 answer:

7 0

Swap x and y's positions

f(x) is another way of saying y, so basically tha initial function is y = 1-2x^3.

Change it up to x = 1-2y^3 and solve for y

X - 1 = - 2y^3

(X - 1)/-2 = y^3

So the cube root of ((x-1)/2) = y

You might be interested in

A high school has a total of 850 students. there are 60 more female students than there are make students?

Mrac [35]

Hey. Let me help you on this one.

Let's break this problem down so it's easier for us to comprehend it.

There are 850 students in the school, and the amount of female students equals to the amount of male students + sixty additional females.

Amount of students in school = 850 students

Male students = $X$

Female students = $X+60$

Let's form an equation so we can work with what we have.

$X+(X+60)=850$

Subtract 60 from both sides.

$X+X=790$

Simplify

$2X=790$

Divide both sides by 2.

$X=395$

Answer: There are 395 male students, and 455 female students.

3 0

3 years ago

Given that 8 bolts and 6 nuts weigh 138grams and 3 bolts and 5 nuts weigh 71 grams. Find the weight of;(a)one bolt and one nut (

Viktor [21]

Answer:

(a) Weight of a bolt = 12 grms and weight of a nut is 7 gms. Weight of one bolt and one nut = 12 + 7 = 19 gms

(b) 69 gms

Step-by-step explanation:

This problem relates to solution of 2 unknowns using simultaneous equations.

Let B be the weight of a single bolt and N be the weight of a single nut

Since 8 bolts and 6 nuts weigh 138 grams we get one of the equations as

8B + 6N = 138 (1)

The second equation in the unknowns is

3B + 5N = 71 (2)

To solve, we eliminate one of the unknowns by making its coefficients the same and subtracting one from the other

Multiplying (1) by 5 ===> 40B + 30N = 690 (3)

Multiplying (2) by 6 ===> 18B + 30N = 426 (4)

(3) - (4) eliminates the N variables and yields

22B = 264 ==> B = 264/22 ==> B = 12

So the weight of a single bolt is 12 grams

We can find the weight of a single nut by substituting this value of B into any of the equations (1), (2), (3) or (4) and solving for N. Let's use equation (2)

3(12) + 5N = 71 ==> 36 + 5N = 71 ==> 5N = 71-36 = 35 ==> N= 7

So the weight of a single nut is 7 grams

Weight of one bolt and one nut is the sum of the above individual weights = 12 + 7 = 19 gms

To solve (b) and (c) we could set up two other equations and plug in values for B and N

(b) 4B + 3N = 4.12 + 3.7 = 69
However, an alternate way is to perceive that 4B + 3N is exactly half of 8B + 6N so the value of that must be 138/2 = 69

11B + 11N = 138 + 71 = 209 which is the equation for the total weight of 11 bolts and 11 nuts

5 0

1 year ago

Find the distance between the two points. Round to the nearest tenth, if necessary. (Point 1 is at (-5,2) and point 2 is at (3,-

aivan3 [116]

Answer:

d = 9.4

Step-by-step explanation:

d= $\sqrt{(3-(-5))^2 +(-3-2)^2\\$