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svet-max [94.6K]
3 years ago
5

Find the equation for the line that passes through (-7,5) that has a slope of 2

Mathematics
2 answers:
Setler79 [48]3 years ago
7 0
Point slope formula y-y1=x(x-x1)
marysya [2.9K]3 years ago
6 0

Answer:

y=mx+b

5=2(-7)+b

5= -14+b

b= 5+14

b = 19

equation -->       y=2x+19

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A jewelry case has a base area of 37.5 sq cm and a height of 1.5 cm ..what is the volume of 6 of these cases
Nina [5.8K]

Answer:

As Per Provided Information

A jewellry case has a base area of 37.5 sq cm and a height of 1.5 cm .

Total Number of these cases are 6 .

We have been asked to determine the volume of these cases .

\bf\: Volume_{(Jewellery  \: Cases)} = Base \: Area \:  \times height \times Total \: number \: of \: Jewellery \:Cases

Let's substitute the given value and we obtain

\sf\longrightarrow\:Volume_{(Jewellery  \: Cases)} = 37.5 \times 1.5 \times 6 \\  \\  \\ \sf\longrightarrow\:Volume_{(Jewellery  \: Cases)} = \: 56.25 \times 6 \\  \\  \\ \sf\longrightarrow\:Volume_{(Jewellery  \: Cases)} = \: 337.5 \:  {cm}^{3}

<u>Therefore</u><u>,</u>

  • <u>Volume</u><u> of</u><u> </u><u>6</u><u> </u><u>jewellery</u><u> </u><u>cases</u><u> </u><u>are </u><u>3</u><u>3</u><u>7</u><u>.</u><u>5</u><u> </u><u>cm</u><u>³</u>
4 0
2 years ago
Read 2 more answers
Which equation has a solution of x = 13?
Nezavi [6.7K]

Answer:

x-10 = 3

Step-by-step explanation:

13- 10 = 3

x=13

4 0
3 years ago
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Please Help! Algebra 2!
eduard

Answer:

The interest rate of the account is 3\%

Step-by-step explanation:

we know that    

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

t=14\ years\\ P=\$1,863\\ A=\$2,830.97\\n=4  

substitute in the formula above  and solve for r

\$2,830.97=\$1,863(1+\frac{r}{4})^{4*14}  

(2,830.97/1,863)=(1+\frac{r}{4})^{56}  

(2,830.97/1,863)^{1/56}=(1+\frac{r}{4})

[(2,830.97/1,863)^{1/56}-1]=\frac{r}{4}    

r=4*[(2,830.97/1,863)^{1/56}-1]\\ \\r= 0.03

Convert to percent

r= 0.03*100=3\%

8 0
3 years ago
Suponga que desea utilizar un servicio de correo particular para enviar un paquete que tiene forma de caja rectangular con una s
statuscvo [17]

a) El volumen de la caja en función de su longitud es:

V_{caja}=\frac{x^{3}}{16}-\frac{25x^{2}}{2}+625x

b) El dominio de la ecuación del volumen son todos los números reales.

c) Las dimensiones del paquete con el mayor volumen posible son:

longitud de la caja  x = 30 plg

lado de la sección transversal L = 17.5 plg

a)

Definamos x como la longitud de la caja y L como el lado de la sección transversal, que es cuadrada para este caso.

Sabemos que la suma de su longitud (x) y el perímetro de la sección transversal (P = 4L) es igual a 100 plg.

x+4L=100 (1)

Ahora, el volumen de esta caja rectangular está dada por:

V_{caja}=A_{base}*x

V_{caja}=L^{2}*x (2)

Pero necesitamos expresar el volumen en función de x.

Despejamos L de la ecuación (1) y remplazarlo en (2).

Por lo tanto el volumen en función de x será.

V_{caja}=(\frac{100-x}{4})^{2}*x

V_{caja}=\frac{x^{3}}{16}-\frac{25x^{2}}{2}+625x

b)

Al ser la función un polinomio de orden 3 el dominio de esta función son todos los numeros reales.

c)

Observando la gráfica de esta función, podemos ver que para un valor aproxiamdo de x = 30 plg el valor de V tiene un punto de inflección, es por definición de maximización de una función que podemos usar ese punto para encontrar las dimensiones de la caja.

Por lo tanto si x = 30 plg el valor de L usando la ecuacion (1) sera:

L=\frac{100-x}{4}

L=\frac{100-30}{4}=17.5\: plg

Por lo tanto la máxima dimensión de la caja es:

x = 30 plg

L = 17.5 plg

Puedes aprender más sobre maximizar funciones aquí:

brainly.com/question/16339052

 

     

 

6 0
3 years ago
Can 15/8 be simplified
Olegator [25]

No it can't

In mixed number form it's 1 7/8

3 0
3 years ago
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