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AVprozaik [17]
2 years ago
15

Please help me I rlly do need help

Mathematics
1 answer:
mixas84 [53]2 years ago
8 0
Option 4 will be the answer:)
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Clara needs $52 to go on a field trip. She has saved $16.50. She earns $6.50 per hour cleaning her neighbor's garden, and she ea
kifflom [539]
Yes, because the total will be $53
3 0
3 years ago
Solve using logs 5^(3x-6)=125
Hitman42 [59]
5 ^{3x-6} =125 \\ \\ 5 ^{3x-6} =5^3 \\ \\3x-6 =3 \ \ |+6 \\ \\3x=3+9 \\ \\3x=12 \ \ /:3 \\ \\x=\frac{12}{3} \\ \\x= 3
3 0
2 years ago
PLEASE HELP ME I WILL MAKE YOU BRAINILIST
Luda [366]

Answer:

It's false because it's actually about 75%.

Step-by-step explanation:

From 15-45 is 3/4 of the plot

4 0
3 years ago
Use the graphs of f and g to solve Exercises 87, 88, and 89.
Nadya [2.5K]

Answers and explanations:

87. The domain of added functions includes the restrictions of both. So the range of the added function in this question is [-4, 3]

88. When finding the domain of a divided function we do the same as adding, but with an extra rule: g can't equal zero. So for this question the domain is (-4, 3)

89. To graph f + g you add the y-values for each x-value. I added a picture to help explain this one!

4 0
3 years ago
The variable z is directly proportional to x. When x is 11, z has the value 44. What is the value of z when x = 21?
dimulka [17.4K]

Directly proportional, both increase/decrease, Multiple k(constant you needed to solve for)..

Inversely --one increases as the other decreases, increase the denominator & fraction gets smaller.... So

Problem:

Dirextly to X (× by X)

Inversely to Y, (÷ by Y)

Z= k X/Y

Solve, working backwards: Z =5 becomes

5 = k (X) ÷ (Y). And

X=15 and Y =9 becomes

5= k(15)/(9). Undo ÷9, ×9 both sides

45= k(15). Now undo ×15 by ÷15 both sides

45/15 = 3. So k=3, (also called your constant of variation)....and your Equation/Proportion becomes...

Z = 3X/Y

Use the new #s.... X=23, Y=14

Z= 3×23÷14 = 69/14. If they want spirochete answer divide and round to corresponding # if decimals

4 0
2 years ago
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