Answer:
1734
Step-by-step explanation:
3 times 17 to find the number of feet =51
51 time $34 (the price per foot ) to find total
The distance from Humood's house to the school is 500m
<h3>How to determine the distance from Humood's house to the school?</h3>
The given parameters are:
Humood's house is (-5,7)
The school is (3,1)
The distance between both points is calculated using
![d = \sqrt{(x_2- x_1)^2 + (y_2 - y_1)^2](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B%28x_2-%20x_1%29%5E2%20%2B%20%28y_2%20-%20y_1%29%5E2)
Substitute the known values in the above equation
![d = \sqrt{(-5 - 3)^2 + (7 - 1)^2](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B%28-5%20-%203%29%5E2%20%2B%20%287%20-%201%29%5E2)
Evaluate
d = 10
Each unit in the graph is 50m.
So, we have
Distance =10 * 50m
Evaluate the product
Distance = 500m
Hence, the distance from Humood's house to the school is 500m
Read more about distance at
brainly.com/question/1872885
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The conversion is
x = magnitude × cos(angle)
y = magnitude × sin(angle)
or
(x, y) = 120.2(cos(119°), sin(119°)) ≈ (-58.27, 105.13)
_____
A suitable graphing calculator handles this easily.
3 log 2x = 4
==> log 2x = 4/3
==> 2x = 10^(4/3)
==> x = \frac{10^(4/3)}{2}