3 different pairs are...
0+1=1
-1+2=1
-2+3=1
A trig identity is <span>asinucosu=<span>a/2</span>sin(2u)</span>So you can write your equation as<span>y=sin(x)cos(x)=<span>1/2</span>sin(2x)</span>Use the crain rule here<span><span>y′</span>=<span>d/<span>dx</span></span><span>1/2</span>sin(2x)=<span>1/2</span>cos(2x)<span>d/<span>dx</span></span>2x=cos(2x)</span>The curve will have horizontal tangents when y' = 0.<span><span>y′</span>=0=cos(2x)</span>On the interval [-pi, pi], solution to that is<span><span>x=±<span>π4</span>,±<span><span>3π</span>4</span></span></span>
Answer:
I would say that the answer is 4/20
<u>Alternate form:</u>
<u>u</u><u>=</u><u>76.48</u>
Answer:
Step-by-step explanation: your going to find the y intercept
find the domain
find the inverse
find the derivative
find the extrema
find the horizontal asymptotes
tell weather its even or odd
but its X=0
