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oksian1 [2.3K]
3 years ago
6

Rectangular prism. A. 5779ft3 B. 1123ft3 C. 4829ft3 D. 2823ft3

Mathematics
1 answer:
FrozenT [24]3 years ago
7 0

Answer:

It would be B I think, I'm not sure tho

Step-by-step explanation:

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A new Youth Activity Center is being built in Hadleyville. The perimeter of the rectangular playing field is 430 yards. The leng
scoundrel [369]

Answer:

Width = 44 yards

Length = 171 yards

Step-by-step explanation:

Given:

<em>Perimeter of the rectangular field = 430 yards.</em>

Let:

<em>The length of the field be L</em>

<em>The width of the field be W.</em>

From the question:

<em>The length of the field is 5yards less than quadruple the width. This implies that;</em>

L = 4W - 5

But.

Perimeter (P) of a rectangle is given by:

P = 2(L + W)       ---------------(i)

Substitute the values of P = 430, L = 4W - 5 and W into equation (i) as follows;

430 = 2(4W - 5 + W)

430 = 2(5W - 5)

430 = 10W - 10

10W = 430 + 10

10W = 440

Divide both sides by 10

W = 44

Therefore, the width of the field is 44 yards.

Remember that,

L = 4W - 5          

[Now substitute W = 44]

L = 4(44) - 5

L = 176 - 5

L = 171

Therefore, the length of the field is 171 yards

8 0
3 years ago
the length of the hypotenuse of 30 degrees 60 degrees and 90 degrees triangle is 16. whats the perimeter
ser-zykov [4K]
<em>The answer you are looking for would be: </em>
<em><u>106 </u></em>
<em><u>Because to find the perimeter you have to add the sides so 30+60=90+16+106 </u></em>
<em>Hope that helps!! </em>
<em>Have a wonderful day!!</em>
6 0
3 years ago
Let divf = 6(5 − x) and 0 ≤ a, b, c ≤ 12. (a) find the flux of f out of the rectangular solid 0 ≤ x ≤ a, 0 ≤ y ≤ b, and 0 ≤ z ≤
dusya [7]
Continuing from the setup in the question linked above (and using the same symbols/variables), we have

\displaystyle\iint_{\mathcal S}\mathbf f\cdot\mathrm d\mathbf S=\iiint_{\mathcal R}(\nabla\cdot f)\,\mathrm dV
=\displaystyle6\int_{z=0}^{z=c}\int_{y=0}^{y=b}\int_{x=0}^{x=a}(5-x)\,\mathrm dx\,\mathrm dy\,\mathrm dz
=\displaystyle6bc\int_0^a(5-x)\,\mathrm dx
=6bc\left(5a-\dfrac{a^2}2\right)=3abc(10-a)

The next part of the question asks to maximize this result - our target function which we'll call g(a,b,c)=3abc(10-a) - subject to 0\le a,b,c\le12.

We can see that g is quadratic in a, so let's complete the square.

g(a,b,c)=-3bc(a^2-10a+25-25)=3bc(25-(a-5)^2)

Since b,c are non-negative, it stands to reason that the total product will be maximized if a-5 vanishes because 25-(a-5)^2 is a parabola with its vertex (a maximum) at (5, 25). Setting a=5, it's clear that the maximum of g will then be attained when b,c are largest, so the largest flux will be attained at (a,b,c)=(5,12,12), which gives a flux of 10,800.
7 0
3 years ago
At this point I’m just gonna post all the questions so stay online. y’all are so smart. 2 more to go! Xoxo &lt;3
spayn [35]

Answer:172.5

Step-by-step explanation:Xoxo

8 0
3 years ago
Bridges 4 grade answer key
Arturiano [62]
Idk but pointsss???????????????
5 0
4 years ago
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