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garri49 [273]
3 years ago
12

Fill in the table of values for the equation y = x + 2​

Mathematics
1 answer:
sweet [91]3 years ago
3 0

Answer:

-3

2

5

Step-by-step explanation:

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There were 30 jelly beans in a jar 2/5 were blue and 1/3 of them were yellow ,how many were green ?
amm1812

Answer:

the answer is 27

Step-by-step explanation:

there were 30 jelly beans 2 - 30 = 28

and 28-1 - 27

<em>Please mark me as brainliest I gave this answer first</em>

8 0
1 year ago
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Antoine and Tess have a disagreement over how to compute a 15% gratuity on $46.00. Tess says, “It is easy to find 10% of 46 by m
Nady [450]

Tess is correct about figuring 10% but he added 2 of them together which is like adding 10% +10% which is 20% not 15%.

 he should have taken 1/2 of the 4.60 for 5% since 5 is half of 10

 half of 4.60 = 2.30

then add that to the 4.60

4.60 +2.30 = 6.90 is 15%

6 0
3 years ago
How many ways are there to select five unordered elements from a set with three elements when repetition is allowed?
Zolol [24]

The number of ways or permutations to select five unordered elements from a set with three elements when repetition is allowed is 243.

According to the given question.

The total number of elements, n = 3

The number of elements to be selected at a time when repetition is  allowed, r = 5

Since, we know that " the number of ways or permutations of n things taken r all at a time, when repetition of things are allowed, is n^{r}.

Therefore,

The number of ways or permutations to select five unordered elements from a set with three elements when repetition is allowed

= 3^{5}

= 243

Hence, the number of ways or permutations to select five unordered elements from a set with three elements when repetition is allowed is 243.

Find out more information about permuations here:

brainly.com/question/13833229

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3 0
1 year ago
A group of married couples takes an IQ test. The average husband's IQ is 105 with an SD of 15 and the average wife's IQ is 110 w
Aloiza [94]

Answer:

Wife' s IQ = 100

0.2% are smarter than their wives.

Step-by-step explanation:

We are given the following information in the question:

Husband:

Mean = 105

SD = 15

Wife:

Mean = 110

SD = 10

Correlation between husband's and wife's IQ = 0.5

a) Let the husbands be represented by X and wives by Y.

Man's IQ = 75

Standardizing the scores, we get:

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

\dfrac{75-105}{15} = -2

We know that if we standardize our scores then:

Z_Y = rZ_X

Putting value, we get:

Z_Y = 0.5(-2) = -1

So,

Y = 110 + (-1)*10 = 100

b) Standard deviation of IQ's of wives married to husbands with IQ of 75 is:

SD = SD_Y\sqrt{1-r^2} = 10\sqrt{1-0.25} = 8.66

We know that a husband of an IQ 75 will have a wife of a mean IQ of 100. So for a man to be smarter than his wife she should have IQ less than 75.

P(Y

8 0
3 years ago
Fill in the blank 31+____=61
saveliy_v [14]
31 plus 30 equals to 61
6 0
4 years ago
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