Question

A jar contains 6 red marbles numbered 1 to 6 and 8 blue marbles numbered 1 to 8. A marble is drawn at random from the jar. Find the probability the marble is red or odd numbered.

Answer 1

Answer:

$P(R\ or\ odd\ Numbered)=5/7$

Step-by-step explanation:

From the question we are told that:

Number of Red Marble $n_r=6$

Number of Blue Marble $n_b=8$

Sample size $n=n_r+n_b$

$n=6+8$

$n=14$

And

No of red or Odd numbered $x= 6+4 = 10$

Generally the equation for  probability the marble is red or odd numbered. is mathematically given by

$P(R or odd Numbered)=x/n$

$P(R or odd Numbered)=10/14$

$P(R\ or\ odd\ Numbered)=5/7$