All categories

3 years ago

Write an equation of the line that passes through (1, -8) and is parallel to the line y = -3x - 7

Mathematics

1 answer:

Anna71 [15]3 years ago

8 0

Answer:

the desired new equation is y = -3x - 5

Step-by-step explanation:

The desired equation of this new (parallel) line has exactly the same form as the given line y = -3x - 7. Only the y-intercept will be different.

Starting with y = -3x - 7, replace x with the x-coordinate of the given point (1, -8) and y with the y-coordinate. We get:

-8 = -3(1) + C, where C is the new y-intercept and is to be determined.

Then C = -5, and the desired new equation is y = -3x - 5.

You might be interested in

Help please I don’t know the answer and the teacher didn’t explain

Diano4ka-milaya [45]

Answer:

Step-by-step explanation:

$\frac{-4d^{2}+15d^{2}}{5}=\frac {11d^{2}}{5}\\\\=\frac{11*1^{2}}{5}\\\\=\frac{11}{5}\\\\=2\frac{1}{5}$

3 0

3 years ago

Which of the following is the product (5y − 3)2?

ololo11 [35]

Answer:

d it is D

Step-by-step explanation:

6 0

3 years ago

Find the area???????

Elan Coil [88]

Area of the top triangle = 0.5 * 3 * 4 = 6

Area of the parallelogram = 4 * 4 = 16

Answer is 22 units^2

5 0

4 years ago

Which statement explains the relationship of sides BA and B'A' after rectangle BADC has been rotated 90° clockwise about the ori

Leni [432]

Answer:

Numbering the options, we have;

1) Side B'A' has a slope of −1 and is perpendicular to side BA.

2) Side B'A' has a slope of 1 and is parallel to side BA.

3) Side B'A' has a slope of 1 and is perpendicular to side BA.

4) Side B'A' has a slope of −1 and is parallel to side BA.

The correct option is;

1) Side B'A' has a slope of -1 and is perpendicular to side BA

Step-by-step explanation:

The given coordinates are;

A(3, 5) B(1, 3), C(5, -1) and D(7, 1)

The slope of BA is found as follows;

$Slope \, of BA= \dfrac{y_{2}-y_{1}}{x_{2}-x_{1}} =\dfrac{3-5}{1-3}= \dfrac{-2}{-2} = 1$

Rotation of a line through 90 degrees gives

(x, y) will be (y, -x)

Therefore, the coordinates of A' = (5, -3)

The coordinates of B' = (3, -1)

Then the slope is given as follows;

$Slope \, of \, B'A' =\dfrac{-1 -(-3)}{3-5}= \dfrac{2}{-2} = -1$

Therefore side B'A' has a slope of -1 and is perpendicular to side BA.

8 0

4 years ago

1.The two triangles are similar. (picture one)

Rus_ich [418]

1. 3x+1=4/5(4x)
15x+5=4(4x)
16x=15x+5
x=5
2. 13x3=39
13x2=26
x=27
x=27

7 0

3 years ago