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Leto [7]
3 years ago
15

Solve the following simultaneous equations using an algebraic (not graphical) method.

Mathematics
1 answer:
ahrayia [7]3 years ago
3 0

Answer:

x=4

y= -1

Step-by-step explanation:

(3x-2y=14)×3

(7x+3y=25)×2

9x-6y= 42

14x + 6y =50

9x-42=6y

-14x+50=6y

9x-42= -14x+50

23x = 92

x=4

3(4)-2y=14

12-2y =14

-2y=2

y= -1

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Tickets for a tour of a city cost $5. A tour will only happen when a total of at least 20 tickets and no more than 45 tickets ha
professor190 [17]

Answer:

y(x)=5x for (20≥x≤40)

Step-by-step explanation:

Step one :

Given data

Cost of ticket =$5

Given that the number of tickets to be sold for the tour to happen should be at least 20 and not more than 40

Step two :

Let the number of tickets be x

And let the revenue or income be y

The function for the cost is expressed linearly as

y(x)=5x

The domain is y(x)=5x for (20≥x≤40)

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3 years ago
Alexander was putting on a theatre show to debut his play. He is charging $2 for child tickets and $5 for adult tickets. His the
Gwar [14]

19 children tickets and 31 adults ticket were sold

2x+5y = 193

Step-by-step explanation:

sold 19 tickets for children  $2  =  19×2 = $38

sold 31  tickets for adult  $5      =  31×5 = $155

Total debut = $38 + $155 =  $193

Total Seats =  19 (children)+ 31 adults)  = 50 seats

2x+ 5y = 193  where x denotes children tickets and y denotes adult tickets

2(19)+5(31) =193

(2×19) + (5×31) = 38 + 155 = 193

(2×19) + (5×31) = 38 + 155 = 193

6 0
4 years ago
Which of the following is true? (5 points) Group of answer choices Tangent is positive in Quadrant I. Sine is negative in Quadra
maks197457 [2]

Answer:

It's A

Please put be the brainlest <3

5 0
3 years ago
A stock has returned of -$1.26 per day . Right and solve an equation to find the number of days until the total return is -$10.0
Schach [20]

Answer:

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3 years ago
Write an expression for the most apparent nth term of the sequence (Assume that n begins with 1) 1,4,7,10,13
kobusy [5.1K]
 The answer is <span>2n * (-1)^(n + 1)

</span><span>The numerator seems to be accelerated via 7 each and every time, so if it starts with the 1st term being one, it incredibly is secure to declare the nth numerator is 7^(n-a million) Likewise, the backside has a million, a million*2, a million*2*3, a million*2*3*4, and a million*2*3*4*5. This seems to be factorials, so we are in a place to declare the nth term interior the denominator is n! putting those mutually, the nth term is 7^(n-a million)/n!
</span>I hope this helped God Bless!
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3 years ago
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