Since it is asking for a perpendicular line, we take the reciprocal of the slope in the given equation to use as the slope for the perpendicular line.

In y = x + 2, m = 1. However, for a perpendicular line we flip and multiply by a negative 1.

(Example: If m = 3, we would take the reciprocal of it and it turns into m = -1/3. If m = - 1/4, we would take the reciprocal of it and it turns into m = 4.)

So, the m = 1 turns into a m = -1.

Now, you can use the point (4,-1) to form a point-slope equation first.

y-(-1) = -1(x-4)

Then, use basic algebra to form a slope-intercept form equation.

y + 1 = -x + 4

y = -x +3

8 0

3 years ago

Which equation has a slope of -5/2 and a y-intercept of -2

const2013 [10]

$\bf \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\qquad \implies y = \stackrel{\stackrel{m}{\downarrow }}{-\cfrac{5}{2}}x\stackrel{\stackrel{b}{\downarrow }}{-2}$

7 0

4 years ago

If s=7 cm and t= 24 cm, what is the length of r?

marin [14]

A^2 + B^2 = C^2.

so 49 + 576 = C^2

625 = C^2

Now find the square root of 625.

25 = C (in your case r)

3 0

4 years ago